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Tom [10]
3 years ago
15

HELP NEEDED ASAP !! VERY MUCH APPRECIATED ! CHEMISTRY

Chemistry
1 answer:
mash [69]3 years ago
5 0
Workings are in the picture! first you get moles of Fe2O3, then you get moles of Al and then you get mass of Al!

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Calculate the density of an aluminum block with a volume of 100 cm3 and a mass of 270g.
m_a_m_a [10]

Answer:

<h2>2.7 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{270}{100}  =  \frac{27}{10} \\

We have the final answer as

<h3>2.7 g/cm³</h3>

Hope this helps you

6 0
2 years ago
A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O 3 ( g ) + NO ( g )
Aleksandr [31]

Answer:

(a) 7.11x10⁻⁴ M/s

(b) 2.56 mol.L⁻¹.h⁻¹

Explanation:

(a) The reaction is:

O₃(g) + NO(g) → O₂(g) + NO₂(g)   (1)

The reaction rate of equation (1) is given by:

rate = k*[O_{3}][NO]     (2)

<u>We have:</u>

k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹

[O₃]₀ = 2.35x10⁻⁶ M

[NO]₀ = 7.74x10⁻⁵ M

Hence, to find the inital reacion rate we will use equation (2):

rate = k*[O_{3}]_{0}[NO]_{0} = 3.91 \cdot 10^{6} M^{-1}s^{-1}*2.35\cdot 10^{-6} M*7.74 \cdot 10^{-5} M = 7.11 \cdot 10^{-4} M/s  

Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s

(b) The number of moles of NO₂(g) produced per hour per liter of air is:

t = 1 h

V = 1 L

\frac{\Delta[NO_{2}]}{\Delta t} = rate

\frac{\Delta[NO_{2}]}{\Delta t} = 7.11 \cdot 10^{-4} M/s*\frac{3600 s}{1 h} = 2.56 mol.L^{-1}.h{-1}

Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹

I hope it helps you!                                

5 0
3 years ago
A student calculates the density of an unknown metal sample to be 8.25 g/cm3
romanna [79]

Answer:

the answer is b

Explanation:

mass=198 divided by volume 24 gives you 8.25

4 0
3 years ago
PLEASE hurry
gizmo_the_mogwai [7]

Answer:

The answer is A.

Explanation:

8 0
3 years ago
Read 2 more answers
An alkane used as a lubricant contains 25 carbon atoms. How many hydrogen atoms are present in its structure?
nadya68 [22]

Answer:

52

Explanation:

Alkanes are saturated hydrocarbons, that is, they are formed just by carbon and hydrogen atoms bonded through single covalent bonds. The general formula for alkanes is CnH2n+2.

If n = 25 (25 carbon  atoms), 2n + 2 = 2 × 25 + 2 = 52. There are 52 hydrogen atoms in the structure and the alkane has the formula C₂₅H₅₂.

5 0
3 years ago
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