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Sever21 [200]
2 years ago
7

(Science) why is the 10g of shampoo is more dense than the 10kg of the same shampoo?

Chemistry
1 answer:
igor_vitrenko [27]2 years ago
6 0
Grams (g) is much lighter than kilograms (kg)
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Which of the following equalities is not correct?
Kryger [21]

1cm^3 = 1L would be the correct answer. One cubic centimeter equals .001 liter, so this equality above is not correct.

Please let me know if you have any questions! :)

8 0
3 years ago
Read 2 more answers
A chemistry student adds a quantity of an unknown solid compound X to 5.00 L of distilled water at 15.° C . After 10 minutes of
Yuliya22 [10]

Answer:

34 g/100 mL

Explanation:

The solubility of a compound can be expressed in g/100mL, for this we must divide the mass of the compound that dissolves in the solute by the volume of the solvent.

The solvent, in this case, is water, and that mass of the solute X that dissolved is the mass that was recovered after the solvent was drained and evaporated. So the solubility of X (S) is:

S = 0.17 kg/5L

S = 170g/5000mL

S = 170g/(5*1000)mL

S = 34 g/100 mL

8 0
2 years ago
Compare the solubility of silver chromate in each of the following aqueous solutions: Clear All 0.10 M AgCH3COO 0.10 M Na2CrO4 0
slavikrds [6]

Solution :

Comparing the solubility of silver chromate for the solutions :

$0.10 \ M \ AgCH_3COO$    -----     Less soluble than in pure water.

$0.10 \ M \ Na_2CrO_4$   ----- Less soluble than in pure water.

$0.10 \ M \ NH_4NO_3$   -----   Similar solubility as in the pure water

$0.10 \ M \ KCH_3COO$   -----   Similar solubility as in the pure water

The silver chromate dissociates to form :

$AgCrO_4 (s) \rightleftharpoons 2Ag^+ (aq) +CrO_4^{2-}(aq)$

When 0.1 M of $AgCH_3COO^-$ is added, the equilibrium shifts towards the reverse direction due to the common ion effect of Ag^+, so the solubility of Ag_2CrO_4 decreases.

Both AgCH_3COO and $KCH_3COO$ are neutral mediums, so they do not affect the solubility.

 

4 0
2 years ago
How many moles are in 400 ml of hydrogen
Nezavi [6.7K]

Answer:

403.176

Explanation:

I hope that the right answer.

8 0
3 years ago
What volume of stock solution and water must you add to prepare 36.25ml of a 1.25M solution
Serjik [45]

Given :

Number of moles , n = 36.25 mol .

Molarity , M = 1.25 M .

To Find :

The volume of water required .

Solution :

Moarity is given by :

M=\dfrac{n}{V}

So , V=\dfrac{n}{M}

Here , n is number of moles and M is molarity .

Putting all values in above equation , we get :

V=\dfrac{36.25}{1.25}\\\\V=29\ L

Therefore , volume of water required is 29 L .

5 0
3 years ago
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