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Mnenie [13.5K]
2 years ago
7

Which of the following reactions would you find in a radioisotope thermal generator?

Chemistry
1 answer:
Mars2501 [29]2 years ago
6 0
The 3rd option


because i’m always right:)
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What do carnivores do and what is another name for them? PLEASE HELP
Genrish500 [490]
1 meat-eating, predatory, predacious. , hopefully this help :)
3 0
2 years ago
Read 2 more answers
100 points to the person who can answer these 4 questions
Vinil7 [7]

Answer:

....,................................

Explanation:

1= A

2=D

3=C

4=C

8 0
2 years ago
Please help!!!!!!!!!!
STatiana [176]
Phosphorus - P - Protons = 15, Electrons = 15, Neutrons = 16 - Non-Metal

Lithium - Li - Protons = 3, Electrons = 3, Neutrons = 4 - Metal

Nitrogen - N - Protons = 7, Electrons = 7, Neutrons = 7 - Non-Metal

Copper - Cu - Protons = 29, Electrons = 29, Neutrons = 34 - Metal

Neon - Ne - Protons = 10, Electrons = 10, Neutrons = 10 - Non-Metal

sorry i don’t know about the other questions but i thought i could help with the table!

Additional Info:

number of protons = atomic number

number of electrons = atomic number

number of neutrons = mass number - atomic number
3 0
3 years ago
What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?
Inessa05 [86]

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

 The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

                           H = 1g/mol

                            N = 14g/mol

                            O = 16g/mol

 Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

                                = 168 + 22 + 56 + 128

                                 = 374u

Empirical weight:

  Empirical formula:

                        C₁₄    H₂₂      N₄     O₈

                         14  :    22 :    4  :     8

   divide by 2:

                          7   :    11    :    2  :    4

     empirical formula  C₇H₁₁N₂O₄

     empirical weight = \frac{molecular weight}{2} = \frac{374}{2} = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

8 0
3 years ago
What is the ph of a solution that contains 1.0 l of 0.10 m ch3cooh and 0.080 m nach3coo after 0.03 moles of naoh added?
zimovet [89]

Answer: pH = 4.996

Explanation:

No of moles = molarity x volume

:• no of moles of CH3COOH = 0.1M x 0.1L

n(CH3COOH) = 0.1mol

Since 0.03mole of NaOH is added, then 0.03 mole of CH3COOH will be converted to the conjugate.

Therefore, Moles of CH3COOH becomes,

0.1 - 0.03 = 0.07 mol

Subsequently, the moles of CH3COONa increases and becomes,

0.08 + 0.03 = 0.11 mol

Using the Hendersom-Hasselbach equation,

pH = pKa + log [Moles of conjugate÷ moles of Ch3COOH]

From literature, pKa of Ch3COOH is 4.8

Thus,

pH = 4.8 + log [0.11/0.07]

pH = 4.8 + 0.1963

pH = 4.996

4 0
3 years ago
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