The unit of concentration in all the data is M. That is molarity or number of moles of solute per liter of solution.
The amount of sample or volume does not varies the concentration of the solution.
Then you only must compare the molarities and the greater the molarity (moles/liter) the greater the concentration or the more is concentrated the solution.
In this case the order is 0.90 M < 1.00 M < 1.45 M < 2.00 M.
And so, we get to the conclusion that the option C. is the most concentrated solution: 800 mL of 2.00 HCl.
N2 + 3 H2 >> 2 NH3
moles NH3 = 11.50 g /17.0307 g/mol=0.6753
the ratio between H2 and NH3 is 3 : 2
moles H2 needed = 0.6753 x 3/2 =1.013
mass H2 = 1.013 mol x 2.106 g/mol=2.042 g
Walking is what i think you are talking about
Answer:
Explanation:
Hello!
In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:
Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:
Which is also the by-mass fraction and in percent it turns out:
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