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Leno4ka [110]
4 years ago
9

Determine the empirical formula for the compound represented by each molecular formula. c2h4

Chemistry
1 answer:
dybincka [34]4 years ago
6 0
Carbon and hydrogen and the number next to is the number of moles
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What is the number of moles of potassium chloride present in 148 g of kcl?
OLga [1]
The number of moles of one substance given the amount in mass can be calculated by the use of the molar mass. This is the mass of a compound per 1 mol of the said substance. For, KCl the molar mass is 74.55 g/ mol

148 g / 74.55 g/mol = 2 mol KCl

Hope this answers the question. have a nice day.
3 0
3 years ago
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A group of science students collect bacterial swabs from several locations inside their school. The collected bacterial swabs ar
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d because they want to detemine the cause of bacterial growth

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4 years ago
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which sample, when dissolved in 1.0 liter of water, produces a solution with the highest boiling point?
andrew-mc [135]
<span>The correct answer is (C) 0.2 mole MgCl2.

according to Van't Hoff factor rule which is the ratio between the actual

concentration of the particles produced when the substance dissolved and

the concentration of the substance as measured from its mass, so here 0.2

mole MgCl2 is the higher van't Hoff factor as it has more ions than other

choices and the higher concentration.

and when the boiling point formula is delta Tb = Kb * m * i.

 when delta Tb is the change in boiling point.

 and Kb is molal boiling point constant

and m is the molality of the solution

and i is Van't Hoff factor.

 so we can see the relationship between i and delta Tb, the greater Van't Hoff factor the higher the boiling point. so 0.2 MgCl2 is the higher boiling point as it is the greater van't Hoff factor.</span>
4 0
3 years ago
Which of the following statements sounds correct to you?
ololo11 [35]
A is correct vegetables cannot be like acids or alkaline because they foods
6 0
3 years ago
Carbon monoxide reacts with oxygen to form carbon dioxide by the following reaction: 2 CO(g) + O2(g) → 2 CO2(g)∆H for this react
MrMuchimi

Answer : The amount of heat released would be, (3) 811.68 kcal

Explanation :  Given,

Moles of carbon monoxide = 12.0 mole

Enthalpy change = -135.28 kcal

The given balanced chemical reaction is,

2CO(g)+O_2(g)\rightarrow 2CO_2(g)

From the balanced chemical reaction we conclude that,

As, 2 moles of carbon monoxide react to release heat = 135.28 kcal

So, 12.0 moles of carbon monoxide react to release heat = \frac{12.0}{2}\times 135.28kcal=811.68kcal

Thus, the amount of heat released would be, 811.68 kcal

4 0
4 years ago
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