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vaieri [72.5K]
3 years ago
8

Suppose we have two boxes; box 1 contains 4 defective and 16 non defective light bulbs. box 2 contains 1 defective and 1 non def

ective light bulb. we roll a fair die one time. if we get a 1 or a 2, we select a bulb at random from box 1. otherwise we select a bulb from box 2. what is the probability that the selected bulb will be defective?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0
1/24 chance
Your welcome
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Use mathematical induction to prove that if L is a linear transformation from V to W, then L (α1v1 + α2v2 +· · ·+αnvn)= α1L (v1)
e-lub [12.9K]

Answer:

The proof is shown in the explanation below.

Step-by-step explanation:

Analysis:

The proof by induction focuses on n. In this case, let n = 1, and L^{1} will be a linear operator since L^{1} = L

The exercise will show that L^{n} is a linear operator on V and that L^{n+1} is also a linear operator on V. This, follows that:

L^{n+1} (av) = L(L^{m}(v_{1}+v_{2})\\                   = L(L^{m} (v_{1} + L^{m}v_{2})\\                   = L(L^{m}v_{1} + L(L^{m}v_{2})\\                   = L^{m+1}(v_{1}) + L^{m+1}(v_{2})

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3 years ago
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Triss [41]

Answer:

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4

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Step-by-step explanation:

3 0
3 years ago
What is missing in the expression -11xu=33
AleksAgata [21]
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3 years ago
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wel

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4 years ago
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lorasvet [3.4K]

Answer:

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Step-by-step explanation:

log7 (1/343)

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3 years ago
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