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vaieri [72.5K]
3 years ago
8

Suppose we have two boxes; box 1 contains 4 defective and 16 non defective light bulbs. box 2 contains 1 defective and 1 non def

ective light bulb. we roll a fair die one time. if we get a 1 or a 2, we select a bulb at random from box 1. otherwise we select a bulb from box 2. what is the probability that the selected bulb will be defective?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0
1/24 chance
Your welcome
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LAST QUESTION ON MY TEST PLEASE HELP
Kipish [7]

Answer:

x = 8

Step-by-step explanation:

For this question, you can use power of a point, more specifically when two secants intersect in the interior of a circle. From this, you get the equation:

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You can simplify and solve:

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3 years ago
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Scorpion4ik [409]
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Elanso [62]
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Since 13/8 = 1 5/8, A and B cannot be correct.

5/8 > 1/2

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7 0
3 years ago
Find the number of units x that produces the minimum average cost per unit C in the given equation. C = 0.001x3 + 5x + 250
Ksju [112]

Answer:

50 units

Step-by-step explanation:

Find the number of units x that produces the minimum average cost per unit C in the given equation.

C = 0.001x³ + 5x + 250

unit cost f(x) = C/x

= 0.001x³/x + 5x/x+ 250/x

f(x) = 0.001x² + 5 + 250/x

f'(x) = 0.002x - 250/x²

We equate the first derivative to zero

0.002x - 250/x² = 0

0.002x = 250/x²

Cross Multiply

0.002x × x² = 250

0.002x³ = 250

x³ = 250/0.002

x³ = 125000

x = 3√(125000)

x = 50 units

Therefore, the number of units x that produces the minimum average cost per unit C is 50 units.

4 0
3 years ago
What is 4/9 in simplest form
blagie [28]
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3 years ago
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