Answer:
a) pH of methylamine = 11.91
b) Volume of milliliters of titrant required to reach equivalence point = 36.59 mL
c) The pH at equivalence point = 5.92
Explanation:
a)
Before the titrant is added; the value for pH of the methylamine is calculated as:
where ;
b)
How many milliliters of titrant are required to reach the equivalence point?
Millimoles of base = (25.00 mL × 0.1500 M) of methylamine = 3.75
3.75 millimoles of HCl is required to reach equivalence point.
3.75 = Volume × 0.1025
Volume of milliliters of titrant required to reach equivalence point = 36.59 mL
c)
The total volume = 36.58 + 25.00 = 61.58 mL
Concentration of the salt; i.e [salt] =
[salt] = 0.061 M
pOH ≅ 8.08
pH = 14 - 8.08
pH = 5.92