1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svetlana [45]
3 years ago
8

Consider an iron-silver voltaic cell that is constructed such that one half-cell consists of the iron, Fe, electrode immersed in

a Fe(NO3)3 solution, and the other half-cell consists of the silver, Ag, electrode immersed in an AgNO3 solution. The two electrodes are connected by a copper wire. The Fe electrode acts as the anode, and the Ag electrode acts as the cathode. To maintain electric neutrality, you add a KNO3 salt bridge separating the two half-cells. Use this information to solve Parts B, C.
B.)The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell is the site of the reduction reaction. Type the half-cell reaction that takes place at the anode for the iron-silver voltaic cell. Indicate the physical states using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for an aqueous solution. Do not forget to add electrons in your reaction. Express your answer as a chemical equation.
C.) The half-cell is a chamber in the voltaic cell where one half-cell is the site of an oxidation reaction and the other half-cell is the site of a reduction reaction. Type the half-cell reaction that takes place at the cathode for the iron-silver voltaic cell. Indicate physical states using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for an aqueous solution. Do not forget to add electrons in your reaction.
Chemistry
1 answer:
Marianna [84]3 years ago
8 0
I think it is c sorry
You might be interested in
How can the conductivity of a salt solution be decreased?
Musya8 [376]

Answer:

B. Add more water to decrease the concentration.

Explanation:

If we add more water to the solution, the concentration is decreased and like wise the conductivity of the solution.

  • Concentration is the amount of solute in a solution.
  • Conductivity deals with the ability of a solution to allow the passage of current.

Concentration and conductivity are directly proportional to one another. The higher the concentration, the higher the conductivity and vice versa.

  • Adding more water increases the amount of solvent and the concentration reduces.
4 0
3 years ago
¿cual es la valencia mas probable para el sodio (Na)que se encuentra en el grupo 1 es?
igomit [66]

Answer:

Hey dude

Explanation:

Can you pls tell me which language I sthis... And tell me it in English.. Pls

6 0
4 years ago
If a compound has a composition of 82% nitrogen and 18% hydrogen, what is the empirical formula for this compound
Damm [24]

Answer: The empirical formula for the given compound is NH_3

Explanation : Given,

Percentage of H = 18 %

Percentage of N = 82 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 18 g

Mass of N = 82 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{18g}{1g/mole}=18moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{82g}{14g/mole}=5.8moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.

For Hydrogen  = \frac{18}{5.8}=3.10\approx 3

For Nitrogen = \frac{5.8}{5.8}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : N = 3 : 1

Hence, the empirical formula for the given compound is NH_3

3 0
3 years ago
Can someone please help its science
anastassius [24]

Answer:

c

Explanation:

6 0
3 years ago
Read 2 more answers
What volume of 6.00m hcl can be made from 319 ml of 6.80m hcl?
velikii [3]
So the mole number of 319 ml of 6.80 M HCl is 6.80*319*10^(-3)=2.17 mol. So the volume of 6.00 M HCl needed is 2.17/6.00=0.362 L=362 ml
8 0
4 years ago
Read 2 more answers
Other questions:
  • Writing net ionic equation. <br><br> Sn(No3)2(aq)+K2S(aq) -&gt; SnS(s)+2KNO3(aq)
    8·1 answer
  • The shape of which continental coastlines provides evidence for the continental drift hypothesis.
    15·2 answers
  • Which cells carry nutrients from food to the rest of the cells in the body?​
    6·2 answers
  • At most, how many covalent bonds can a phosphorous atom form? <br><br>(A) 1<br>(B2<br>(C)3<br>(D)4 ​
    8·1 answer
  • How does the height to which each ball bounces back relate to the law of conservation of energy?
    8·1 answer
  • Liquid hexane CH3CH24CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O .
    6·1 answer
  • What best explains the type of energy present in natural gas? It is chemical energy, which is a type of kinetic energy. It is ch
    12·1 answer
  • I need this very fast so please answer this first! I will mark you as the Brainiest and put my max points so please hurry!!!
    12·2 answers
  • Answer:<br><br>1.<br>2.<br>3.<br>4.<br>5.<br>6.<br>7.<br>8.<br>9.<br>10.​
    5·1 answer
  • BRAINLIEST!!
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!