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muminat
3 years ago
10

Find the real values of x and y -4+3i-x+yi=8-6i

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

x = - 12, y = - 9

Step-by-step explanation:

Given

- 4 + 3i - x + yi = 8 - 6i

Simplify left side by collecting like terms and equate like coefficients with the terms on the right side, that is

- 4 - x + i(3 + y) = 8 - 6i, thus

3 + y = - 6 ( subtract 3 from both sides ) ← equating imaginary parts

y = - 9, then

- 4 - x = 8 ( add 4 from both sides ) ← equating real parts

- x = 12 ( multiply both sides by - 1 )

x = - 12

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Answer:

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3 years ago
Find the y-intercept and x-intercept of the line.<br> – 3x+9y= 14
pickupchik [31]

Answer:

\huge\boxed{x-intercept=-\dfrac{14}{3}=-4\dfrac{2}{3}}\\\boxed{y-intercept=\dfrac{14}{9}=1\dfrac{5}{9}}

Step-by-step explanation:

-3x+9y=14\\\\x-intercept\ \text{for}\ y=0:\\\\-3x+9(0)=14\\-3x+0=14\\-3x=14\qquad\text{divide both sides by (-3)}\\\boxed{x=-\dfrac{14}{3}=-4\dfrac{2}{3}}}

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3 0
2 years ago
Please help it would be very appreciated!!
Leto [7]

Answer:

answer is 24.56cm

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7 0
2 years ago
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4 0
2 years ago
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I'm not entirely sure what you're asking, however we know that:

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6 0
3 years ago
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