Answer:
it will send the message through the axon
Answer:
the frequency of photons ![v = 1.509\times10^{39}Hz](https://tex.z-dn.net/?f=v%20%3D%201.509%5Ctimes10%5E%7B39%7DHz)
Explanation:
Given: first ionization energy of 1000 kJ/mol.
No. of moles of sulfur = 1 mole
![\Delta E_1 = 1000KJ/mol](https://tex.z-dn.net/?f=%5CDelta%20E_1%20%3D%201000KJ%2Fmol)
We know that plank's constant
![h = 6.626\times10^{-34} Js](https://tex.z-dn.net/?f=h%20%3D%206.626%5Ctimes10%5E%7B-34%7D%20Js)
Let the frequency of photons be ν
Also we know that ΔE = hν
this implies ν = ΔE/h
![= \frac{10^6J}{6.626\times10^{-34} Js}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B10%5E6J%7D%7B6.626%5Ctimes10%5E%7B-34%7D%20Js%7D)
![v = 1.509\times10^{39}Hz](https://tex.z-dn.net/?f=v%20%3D%201.509%5Ctimes10%5E%7B39%7DHz)
Hence, the frequency of photons ![v = 1.509\times10^{39}Hz](https://tex.z-dn.net/?f=v%20%3D%201.509%5Ctimes10%5E%7B39%7DHz)
Answer:
![\frac{1}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B24%7D)
Explanation:
Given:
For a school event, 1/6 of the athletic field is reserved for the fifth -grade classes and the reserved part of the field is divided equally among the 4 fifth grade classes in the school.
To find: fraction of the whole athletic field reserved for each fifth class
Solution:
Fraction of the whole athletic field reserved for four fifth classes = ![\frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D)
So, fraction of the whole athletic field reserved for each fifth class = ![\frac{1}{4}(\frac{1}{6})=\frac{1}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%28%5Cfrac%7B1%7D%7B6%7D%29%3D%5Cfrac%7B1%7D%7B24%7D)
Answer:
1) 1,... 2
2) 18
3) n= 3 and I=1
Explanation:
1) when l= 0, its an s-sub-level, and only 1 orbital is possible which can carry only 2-electrons
2) the maximum number of electron is given by 2n^2= 2×3^2= 18
3) in 3p, the coefficient of p is the value of n= 3 and l-value of P is 1
Sent a pic that shows the work and answer is in box.