Answer:
Ka = 1.52 E-5
Explanation:
- CH3-(CH2)2-COOH ↔ CH3(CH2)2COO- + H3O+
⇒ Ka = [H3O+][CH3)CH2)2COO-] / [CH3(CH2)2COOH]
mass balance:
⇒<em> C</em> CH3(CH2)2COOH = [CH3(CH2)2COO-] + [CH3(CH2)2COOH] = 1.0 M
charge balance:
⇒ [H3O+] = [CH3(CH2)2COO-]
⇒ Ka = [H3O+]²/(1 - [H3O+])
∴ pH = 2.41 = - Log [H3O+]
⇒ [H3O+] = 3.89 E-3 M
⇒ Ka = (3.89 E-3)² / ( 1 - 3.89 E-3 )
⇒ Ka = 1.519 E-5
Answer:
C
Explanation
On the reactants side there is 4 Hydrogen atoms in total and two oxygen atoms on the left however on the right there is two hydrogen atoms and one oxygen atom. Leaving this equation unbalanced
Answer:
4.49dm3
Explanation:
2NH4Cl + Ca(OH)2 —> CaCl2 + 2NH3 + 2H2O
First, we need to convert 10g of ammonium chloride to mole. This is illustrated below:
Molar Mass of NH4Cl = 14 + (4x1) + 35.5 = 53.5g/mol
Mass of NH4Cl = 10g
Number of mole = Mass /Molar Mass
Number of mole of NH4Cl = 10/53.5 = 0.187mol
From the equation,
2moles of NH4Cl produced 2 moles of NH3.
Therefore, 0.187mol of NH4Cl will also produce 0.187mol of NH3
Now we can obtain the volume of NH3 produced by doing the following:
1mole of any gas occupy 24dm3
Therefore, 0.187mol of NH3 will occupy = 0.187 x 24 = 4.49dm3
