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nikklg [1K]
3 years ago
10

A 1.00 g sample of a hydrogen peroxide (H2O2) solution is placed in an Erlenmeyer flask and diluted with 20 mL of 1 M aqueous su

lfuric acid. To this solution is added 0.0200 M KMnO4 solution via a buret, until a pale purple color persists. This requires 22.50 mL of KMnO4 solution. What is the percent by mass of hydrogen peroxide in the original solution? (A) 0.613% (B) 1.53% (C) 3.83% (D) 7.65%
Chemistry
1 answer:
mihalych1998 [28]3 years ago
3 0
The percent by mass is0.613
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Protons Ha and Hb in the compound given are _________. homotopic enantiotopic diastereotopic mesotopic none of these
jek_recluse [69]

Protons Ha and Hb in the compound given are enantiotopic.

<h3>What are enantiotopic protons?</h3>

Enantiotopic protons can be defined as those protons that can be replaced by another groups like deuterium.

<h3>What is a compound?</h3>

A compound is a substance which contains two or more elements chemically combined together.

So therefore, Protons Ha and Hb in the compound given are enantiotopic.

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8 0
2 years ago
A fire is an example of ________________ reaction, because heat is _____________ the system.
Over [174]

d. exothermic; leaving

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  • A fire is an example of combustion.
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8 0
3 years ago
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Describe what happens as ice changes to water.
morpeh [17]

Answer:

The energy of the particles increase and the molecules move more quickly.

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8 0
3 years ago
The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

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