The answer is: (5696 J) / (155 g) / (40.0 - 25.0)°C = 2.45 J/g·°C
Answer:
T₂ = 317.87 K
Explanation:
Given data:
Initial pressure = 15 atm
Final pressure = 16 atm
Initial temperature = 298 K
Final temperature = ?
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
15 atm / 298K = 16 atm/T₂
T₂ = 16atm × 298 K / 15 atm
T₂ = 4768 atm. K / 15 atm
T₂ = 317.87 K
Answer:
223 g O₂
Explanation:
To find the mass of oxygen gas needed, you need to (1) convert moles Al to moles O₂ (via the mole-to-mole ratio from reaction coefficients) and then (2) convert moles O₂ to grams O₂ (via the molar mass). When writing your ratios/conversions, the desired unit should be in the numerator in order to allow for the cancellation of the previous unit. The final answer should have 3 sig figs because the given value (9.30 moles) has 3 sig figs.
4 Al + 3 O₂ ----> 2 Al₂O₃
^ ^
Molar Mass (O₂): 32.0 g/mol
9.3 moles Al 3 moles O₂ 32.0 g
------------------- x --------------------- x -------------------- = 223 g O₂
4 moles Al 1 mole
Answer:
C
Explanation:
It afffects changes in pressure and temperature not melting and boiling points
