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2 years ago

How many moles of water can be obtained from the reaction of 4 moles of O2?

Chemistry

1 answer:

Yuliya22 [10]2 years ago

6 0

Answer: 8moles

Explanation:

The reaction below shows the formation of 2 moles of water from 2 moles of hydrogen and 1 mole of oxygen respectively.

2H2(g) + O2 (g) --> 2H2O(l)

So, if 1 mole of O2 produce 2 mole of H2O

4 moles of O2 will produce Z mole of H2O

To get the value of Z, cross multiply

1 x Z = 4 x 2

Z = 8

So, the equation will be 8H2(g) + 4O2 (g) --> 8H2O(l)

Thus, 4 moles of O2 will produce 8moles of H2O .

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Why are pipes bursting in the in extremely cold weather?

avanturin [10]

Water is the only common substance that when you freeze it, it's volume INCREASES.

When the pipe originally held the "all full" volume and the the water expanded, it put a tremendous amount of pressure on the pipe. Enough pressure and the pipe would burst.

8 0

2 years ago

Setting up a one-step unit conversion A student sets up the following equation to convert a measurement. (The ? stands for a num

Aneli [31]

Answer:

0.0008 m

Explanation:

We are given that 0.080 cm

We have to convert 0.080 cm into meter

To find the value of 0.080 cm in meter we are using unitary method

We know that

100 cm =1 m

1 cm = $\frac{1}{100} m$

Therefore, 0.080 cm = $\frac{1}{100}\times 0.080 m$

0.080 cm = $\frac{1}{100}\times \frac{80}{1000}m$

0.080 cm = $\frac{8}{10000}m$

0.08cm=0.0008 m

Hence, the value of 0.080 cm is equal to 0.0008 meter .

7 0

2 years ago

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

4 0

2 years ago

Enthalpies of reaction calculated from bond energies and from enthalpies of formation are often, but not always, close to each o

jolli1 [7]

The enthalpy change in a reaction is given by-

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

This can be expressed in terms of bond energy as-

ΔH°rxn = BEreactants - BEproducts

Therefore, the calculated bond energy according to the above equation will be-

ΔH°rxn = [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H) ] - [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H) = 0 kJ/mol

<h3>What is enthalpy change?</h3>

Enthalpy change is a measure of the energy emitted or consumed in a reaction. This can be determined using the following equation which involves standard enthalpy of reactant and product formation:

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

<h3>What is bond energy?</h3>

Bond energy is defined as the amount of energy needed to dissociate a mole of molecules into their individual atoms.

Learn more about the Enthalpy Change here:

brainly.com/question/14047927

#SPJ4

6 0

1 year ago

Describe how the height of the tides changes from Monday to Thursday.

adoni [48]

One of the results is that the moon is near the earth and the other one, the oceans tide. Even though the earth can hold any object within
ts proximity, the ocean is partly attracted due to its liquid property. At night, the ocean tends to be attracted to the moon by creating a bulge and assigning it as ‘high tide’. This is due to the strong gravitational pull of th moon to the earth.

I hope this helps!
This might be right..

5 0

3 years ago