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Svetradugi [14.3K]

4 years ago

7

There are 16 girls in a school club. the number of girls is four more than twice the number of boys. find the number of boys.

1 answer:

Serhud [2]4 years ago

3 0

The number of boys . . . . . B
Twice the number of boys . . . 2B
4 more than twice the number of boys . . . 2B+4

You said that the number of girls is equal to that, so . . . G = 2B+4

But you also told us what G is: 16 = 2B+4

Subtract 4 from each side: 12 = 2B

Divide each side by 2 : 6 = B

There you have it. There are 6 boys in the club.

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Answer:

The total worth of the investment after 6 months is T = $ 1004004

The geometric mean of the above monthly returns is $\= G = 0.001$

Step-by-step explanation:

From the question we are told that

The growth for each month are

R1 = -0.4, R2= 0.67, R3 = 1.0, R4 = -0.5, R5 = 0.2, R6 = -0.165

The amount invested is $A = \$ 1,000,000$

The number period of the investment is 6 months

Generally the worth of the investment after each month is

$G_i = G_p * (1 + R_i)$

Here $G_p$ is the worth of the investment the previous year

$R_i$ is the growth for that month

So considering the first month

$G_1 = G_p (1 + R_1)$

Here $G_p = A$

So

$G_1 = 1000000 (1 -0.4)$

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Considering the second month

Here $G_p = 600000$

So

$G_2 = 600000 (1 + 0.67)$

=> $G_2 = 1002000$

Considering the third month

Here $G_p = 1002000$

So

$G_3 = 1002000 (1 + 1)$

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Considering the fourth month

Here $G_p = 2004000$

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$G_4= 1002000$

Considering the fifth month

Here $G_p = 1002000$

So

$G_5= 1002000 (1 + 0.2)$

$G_5= 1202400$

Considering the six month

Here $G_p = 1202400$

So

$G_6= 1202400 (1 -0.165)$

$G_6= 1004004$

Generally the total worth of the investment after 6 months is T = $ 1004004

Generally the geometric mean of the monthly returns is

$\= G = \sqrt[n]{ [(1 + R_1 ) * \cdots (1 + R_n)} ]-1$

Here n represents the number of months which has a value n = 6

So

$\= G = \sqrt[6]{[(1+ (-0.4 )) * (1 + 0.67) * \cdots * (1 + (-0.165))]} - 1$

$\= G = 0.001$

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