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timofeeve [1]
4 years ago
6

Identify and give all the appropriate names for three different quadrilaterals or other geometric figures in this Navajo eye-daz

zler design. Anyone?

Mathematics
1 answer:
yaroslaw [1]4 years ago
4 0
You have a bunch of interesting figures there (check the diagram):
- square (in red)
- parallelogram (in green)
- Isosceles trapezoid (in yellow)
- Isosceles triangles (blue, and purple)
Notice that you have more than one of the same figures: a bunch of small isosceles triangles, tow isosceles trapezoids, two big isosceles triangles... etc.

You might be interested in
6 - 3x = 5x - 10x + 8
Jet001 [13]

Answer:

x=1

Step-by-step explanation:

6-3x=5x-10x+8=

move all terms to the left:

6-3x-(5x-10x+8)=0

add all the numbers together, and all the variables

-3x-(-5x+8)+6=0

get rid of parentheses

-3x+5x-8+6=0

add all the numbers together, and all the variables

2x-2=0

move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

3 0
3 years ago
The area of a field shaped like a right triangle is 750yd^2.One leg of the field is fenced with wood costing $5/yd. the remainde
Elenna [48]
Assume that
 a and b = the two legs of the right triangle. 
 c =  the hypotenuse.

The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500               (1)

The perimeter is 150yd, therefore
a + b + c = 150         (2)

Let the side fenced with wood be a, at $5/yd.  Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
 5a + 10b + 10c = 1200            
or
a + 2b + 2c = 240         (3)

From (2), obtain 
c = 150 - a - b              (4)

Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60

From (1), obtain
60b = 1500
b = 25

From (4), obtain
c = 150 - 60 - 25 = 65

Answer:
A. The length of the leg fenced with wood is 60 yd.
B.  The length of the leg fenced with steel is 25 yd.


5 0
3 years ago
Just ignore number 7 it’s 8 I need help on, it tried to attempt it myself but it wasn’t working for me
ArbitrLikvidat [17]

1 hm=100m

1.5hm=150 meters each tower is from each other.

500km(1000m/1km)=500,000 meters the wire covers.

500,000/150 = 3333.33 towers. Just because we want to be safe and have enough towers we can say we have 3334 towers in the span of 500,000 meters.

B)

1kV=1000V

500kV(1000V/1kV)= 500,000 V

There are 1.2 volts in a AA battery so we divide 500,000/1.2 = 416666.67 times larger

3 0
3 years ago
CAN ANYBODY HELP ME ON THIS QUESTION PLEASEEEEEEEEEE HELPPPPPPPP ME ASAP
laila [671]
I think the answer is 4/12 or 1/3
7 0
3 years ago
Please show your work<br> What is the solution of the equation <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%2B13%7D%20-5%3D
Hatshy [7]
Add the five to each side.
then square it to get rid of the square root
2x+13=(5+x)^2
2x+13=x^2+10x+25
2x=x^2+10x+12
x^2+8x+12=0
(x+6)(x+2)
x+6=0
x+2=0
answers are -2 and -6, however, when pluging -6 in it doesnt work, so it is only -2.
3 0
3 years ago
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