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marshall27 [118]
3 years ago
14

Why is it important to learn about fuels and gases?

Chemistry
1 answer:
Blababa [14]3 years ago
6 0
Because you would want to know how they harm and benefit you.
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A 46.2 mL,0.568 M calcium nitrate solution is mixed with 80.5mL of 1.396M calcium nitrate solution.Calculate tge concentration o
Ne4ueva [31]

Answer:

1.09 M

Explanation:

Let's define the equation that will be used to calculate the final concentration of the resultant calcium nitrate solution. In order to calculate it, we need to find the total number of moles of calcium nitrate and divide by the total volume of the resultant solution:

c=\frac{n}{V}

This equation firstly helps us find the number of moles of calcium nitrate. Multiplying molarity by volume will yield the moles. Adding the moles from the first component to the second component will provide us with the total number of moles of calcium nitrate:

n_{Ca(NO_3)_2}=46.2 mL\cdot0.568 M+80.5 mL\cdot1.396 M=138.62 mmol

Now, the total volume of this solution can be found by adding the volume values of each component:

V_total=46.2 mL+80.5 mL=126.7 mL

Finally, dividing the moles found by the total volume will yield the final molarity:

c_{final}=\frac{138.62 mmol}{126.7 mL}= 1.09 M

6 0
3 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
3 years ago
Acetone is the main chemical in nail polish and has a density of 0.7857 g/mL. What is the volume of 6.54g of acetone ?
trapecia [35]

8.3mL

Explanation:

Given parameters:

Mass of acetone = 6.54g

Density of acetone = 0.7857 g/mL

Unknown:

Volume of acetone = ?

Solution:

Density is defined as the mass per unit volume of a substance. It is expressed mathematically as shown below:

  Density = \frac{Mass}{Volume}

Since the unknown is volume, we make it the subject of the formula

Volume =  \frac{mass}{density}

Input the values;

  Volume = \frac{6.54}{0.7857} = 8.3mL

learn more:

Volume brainly.com/question/2690299

#learnwithBrainly

5 0
3 years ago
(c) Polar solutes were separated by hydrophilic interaction chromatography (HILIC) with a strongly polar bonded phase. How would
Lelu [443]

Answer:

(c) The retention time would be higher (d) The retention time would be lower.

Explanation:

For the polar solutes which were separated using the hydrophilic interaction chromatography (HILIC) with a strongly polar bonded phase, the retention time would be higher if eluent were changed from 80 vol% to 90 vol% acetonitrile in water.

However, for the polar solutes which were separated using the normal-phase chromatography on bare silica with methyl t=butyl ether and 2-propanol solvent, the retention time would be lower if the eluent were changed from 40 vol% to 60 vol% 2-propanol.

5 0
3 years ago
Imagine you need to explain to a friend how to convert a value on a food label to one that is measured in grams. Assume the pack
Mariulka [41]

Answer:

453.592 grams

Explanation:

Given

Mass = 1 lb

Required.

Convert to grams using dimensional analysis

Represent 1 lb with x g

In unit conversion, we have that.

1 lb = 453.592 g

So:

Getting the equivalent of lb in g, we have:

x g = 1 lb * (453.592 g/ 1 lb)

x g = 1 * 453.592 g

x g = 453.592 grams

Hence:

The equivalent of 1 lb in grams is 453.592 grams

4 0
3 years ago
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