If the activation energy required for a chemical reaction were reduced, what would happen to the rate of the reaction?The rate w
1 answer:
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Answer:
Explanation:
The kinetic energy possessed by particles will be
where,
M is the mass of the particle (7920938.3 MeV/c²)
c is the speed of the light
Also,
energy of the proton particle =
where,
v is the velocity
m_p is the mass of the proton (938.3 MeV/c²)
since the energy is equal
thus,
or
substituting the values in the above equation, we get
or
Hence,<u> the speed necessary for the specified condition to occur is </u><u>0.9714 times the speed of the light</u>
Answer:
The answer to the question is;
The rate at which the distance between the two cars is changing is equal to 14.4 ft/sec.
Explanation:
We note that the distance traveled by each car after 4 seconds is
Car A = 19 ft in the west direction.
Car B = 26 ft in the north direction
The distance between the two cars is given by the length of the hypotenuse side of a right angled triangle with the north being the y coordinate and the west being the x coordinate.
Therefore, let the distance between the two cars be s
we have
s² = x² + y²
= (19 ft)² + (26 ft)² = 1037 ft²
s = = 32.202 ft.
The rate of change of the distance from their location 4 seconds after they commenced their journeys is given by;
Since s² = x² + y² we have
→ which gives
We note that the speeds of the cars were given as
Car B moving north = 12 ft/sec, which is the y direction and
Car A moving west = 8 ft/sec which is the x direction.
Therefore
= 12 ft/sec and
= 8 ft/sec
becomes
= 464 ft²/sec
= 14.409 ft/sec ≈ 14.4 ft/sec to one place of decimal.