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padilas [110]
3 years ago
13

The density of a material is 22.5 g/cm^3.Express this in SI units.​

Physics
1 answer:
serg [7]3 years ago
8 0

Answer:

22500kg/m³

Explanation:

SI unit is kg/m³

1g/cm³=1000kg/m³

22.5g/cm³=?

22.5 * 1000

=22500kg/m³

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4 years ago
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A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.60 m/s. How
kirill115 [55]

Answer:

Efriction = 768.23 [kJ]

Explanation:

In order to solve this problem we must use the principle of energy conservation. Where it tells us that the energy of a system plus the work applied or performed by that system, will be equal to the energy in the final state. We have two states the initial at the time of the balloon jump and the final state when the parachutist lands.

We must identify the types of energy in each state, in the initial state there is only potential energy, since the reference level is in the ground, at the reference point the potential energy is zero. At the time of landing the parachutist will only have potential energy, since it reaches the reference level.

The friction force acts in the opposite direction to the movement, therefore it will have a negative sign.

E_{pot}-E_{friction}=E_{kin}

where:

E_{pot}=m*g*h\\E_{kin}=\frac{1}{2}*m*v^{2}

m = mass = 56 [kg]

h = elevation = 1400 [m]

v = velocity = 5.6 [m/s]

(56*9.81*1400)-E_{friction}=\frac{1}{2}*56*(5.6)^{2}\\769104 -E_{friction}= 878.08 \\E_{friction}=769104-878.08\\E_{friction}=768226[J] = 768.23 [kJ]

4 0
3 years ago
A helium-neon laser (λ = 633 nm) illuminates a single slit and is observed on a screen 1.50 m behind the slit. The distance betw
mario62 [17]

Answer:

0.2 mm

Explanation:

As we know that

Y = \frac{m\lambda * D}{d}

where

m represents  the order of minimum

y represents the  distance on the screen of the minimum from central axis

λ is the wavelength  of the light

D is the distance between  screen-to-slit

d represents the width of the slit

For first minima

y_1 = \frac{1 * 633 * 10^{-9}*1.5}{d}

For second minima

y_2 = \frac{2 * 633 * 10^{-9}*1.5}{d}

Y_2 - Y_1 = 0.00475m\\\frac{633 * 10^{-9} * 1.5 }{d} = 0.00475\\d = 0.0002 m\\d = 0.2 mm

3 0
3 years ago
Isaiah has samples of two different elements, one metal and one nonmetal
ElenaW [278]

Answer:

1/ As a metal has higher melting point than a nonmetal has, we can guess that sample A is a metal.

2/ The melting point is over 1000 gradius Celcius: 1083 - it's not a low value. And as the sample conducts heat, it is not the element of period N3 in the periodic table, because elements in period 3 do not conduct electricity.

Explanation:

I can not see what the questions 2-3 in your picture is. I answered the question above the table: What can the student conclude about thenidentity of Sample A.

7 0
4 years ago
I will give you BRAINILIEST!!!!!!!!! AND 15 POINTS
Zigmanuir [339]
Hello.

The best answer would be A.Rift Valley.

It forms when l tectonical plates move away froem each other.


Have a nice day :)
4 0
3 years ago
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