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Reika [66]
3 years ago
8

The energy necessary to overcome the attractions of electrons to the nucleus of an atom so as to remove electrons from the atom

is called _____. electron energy charging energy electrical energy ionization energy
Chemistry
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

The answer to your question is below.

Explanation:

The energy necessary to overcome the attractions of electrons to the nucleus of an atom so as to remove electrons from the atom is called _<u>ionization energy</u>.

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Which of the following is a characteristic of the lanthanides?
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Answer:

A

Explanation:

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3 0
3 years ago
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22.4l of ammonia is reaxts with 1.406 mole of oxygen to produce NO and h2o .1.what volume of no is produced at ntp​
IceJOKER [234]

Answer:

The volume of NO is 22.4L at STP

Explanation:

Based on the reaction:

2NH3 + 5/2O2 → 2NO + 3H2O

<em>2 moles of NH3 react with 5/2 moles of O2 to produce 2 moles of NO.</em>

<em />

To solve this question, we need to find the moles of each reactant in order to find the limiting reactant as follows:

<em>Moles NH3 -Molar mass: -17.01g/mol-</em>

Using PV = nRT

PV/RT = n

<em>Where P is pressure = 1atm at STP</em>

<em>V is volume = 22.4L</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 273.15K</em>

1atm*22.4L/0.082atmL/molK*273.15K = n

n = 1.00 moles of NH3

For a complete reaction of 1.00 moles of NH3 are needed:

1.00 moles NH3 * (5/2moles O2 / 2moles NH3) = 1.25 moles of O2

As there are 1.406 moles of O2, <em>the limiting reactant is NH3</em>

<em />

The moles of NO produced are the same than moles of NH3 because 2 moles of NH3 produce 2 moles of NO. The moles of NO are 1.00 moles

And as 1.00moles of gas are 22.4L at STP:

<h3>The volume of NO is 22.4L at STP</h3>

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3 years ago
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What is an electrochemical cell?
vredina [299]

A. Two electrodes separated by an electrolyte that can generate an electrical current.

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a prescriber has ordered childrens motrin 400 mg po q6h for a child who weighs 60 kg. how many mg/kg is the child receiving
DedPeter [7]

Answer:

6.67 mg/kg     per dose   ( 26.67 mg/kg   per day)

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