Question

Separate 945 into 3 parts so that the second part is three times the first part and the third part is double the second part

Answer 1

Let the first part be $x$

The second part is three times the first part, so it is $3x$

The third part is twice the second, so it is $2\cdot 3x = 6x$

In total, you have

$x+3x+6x = 10x = 945$

So, the first part is

$x = \dfrac{945}{10}=94.5$

The second is three times the first, so it is

$94.5 \cdot 3 = 283.5$

The third part is twice the second, so it is

$283.5 \cdot 2 = 567$

In fact, you have

$567 + 283.5 + 94.5 = 945$