Question

A differential manometer is used to measure the drop in pressure across a filter at a water (rho = 1.00 g/cm3) processing plant. The density of the manometer fluid is 6.75 g/cm3. The height of the manometer fluid on side 1 is 2.80 × 102 mm. The height of the manometer fluid on side 2 is 309 mm. What is the pressure difference between points 1 and 2 in psi?

Answer 1

Answer:

The pressure difference between points 1 and 2 is 0.19119 psi.

Explanation:

Given that,

Density of manometer fluid = 6.75 g/cm³

Height of side 1$H= 2.80\times10^{2}\ mm$

Height of side 2= 309 mm

We need to calculate the pressure difference between points 1 and 2

Using balancing pressure at height 1 and 2

$P_{1}+\rho_{w} g(H_{2}-H_{1})=P_{2}+\rho_{l}g(H_{2}-H_{1})$

$P_{2}-P_{1}=\rho_{l}g(H_{2}-H_{1})-\rho_{w}g(H_{2}-H_{1})$

$P_{2}-P_{1}=g(H_{2}-H_{1})(\rho_{l}-\rho_{w})$

$P_{2}-P_{1}=9.8(0.309-0.00280\times102)(6750-1000)$

$P_{2}-P_{1}=1318.59\ Pa$

$\Delta P=1318.59\ Pa$

$\Delta P=1318.59\times0.000145$

$\Delta P=0.19119\ psi$

Hence, The pressure difference between points 1 and 2 is 0.19119 psi.