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JulijaS [17]
2 years ago
9

HELP. I can’t figure this problem out.

Chemistry
2 answers:
Kitty [74]2 years ago
8 0
The answer is C, 1,4-dichloro-2-pentanone.
solong [7]2 years ago
5 0
I believe the answer is C

You might be interested in
Constance has an apple that weighs 85,000 milligrams and a peach that weighs 0.15 kilograms. which fruit has the greater mass? c
Rama09 [41]

The fruit which has the greater mass is peach i.e. 150 grams.

<h3>What is mass?</h3>

Mass is a quantity which is used to define that what amount of substance will occupy any space or present in the given object.

We have given,

Weight of apples = 85,000 mg

Weight of peach = 0.15 kg

To compare the quantity first we have to convert both of these units in the same unit, and we know that:

In 1 kilogram = 1000 grams

And in 1 grams = 1000 milligrams

So, we convert both the units into grams as:

85,000 mg =  85,000 / 1000 = 85 grams

0.15 kg = 150 grams

So, the mass of peach is high.

Hence, peach has the greater mass.

To know more about mass, visit the below link:

brainly.com/question/15526412

4 0
2 years ago
What is the concentration of bromide, in ppm, if 12.41 g MgBr2 is dissolved in 2.55 L water.
pav-90 [236]

Answer:

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

Explanation:

ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.

In our case we have:

mass of MgBr₂ = 12.41 g

volume of water (which is equal to the final solution volume) = 2.55 L

Now we devise the following reasoning:

if         12.41 g of MgBr₂ are dissolved in 2.55 L of water

then         X g of MgBr₂ are dissolved in 1 L of water

X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂

if in         184 g (1 mole) of MgBr₂ we have 160 g of Br⁻

then in   4.867 g of MgBr₂ we have Y g of Br⁻

Y = (4.867 × 160) / 184 = 4.232 g of bromide (Br⁻)

4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

7 0
3 years ago
You are given 230 grams of a substance with a half-life of 0.75 years. How much will remain after 3 years?
Degger [83]
After 3 years, the substance will go through 4 half lives. You can do 230*(1/2)^4, which is 14.375.
6 0
3 years ago
A mixture of gases contains 4.46 moles of neon (Ne), 0.74 mole of argon (Ar), and 2.15 moles of xenon (Xe). Calculate the partia
viva [34]

Explanation:

The partial pressure of an individual gas is equal to the total pressure of the mixture multiplied by the mole fraction of the gas.

Total pressure = 2atm

Mole Fraction = number of moles / total number of moles

Neon

Mole Fraction = 4.46 / 7.35 = 0.607

Partial Pressure = 0.607 * 2 = 1.214 atm

Argon

Mole Fraction = 0.74 / 7.35 = 0.101

Partial Pressure = 0.101 * 2 = 0.202 atm

Xenon

Mole Fraction = 2.15 / 7.35 = 0.293

Partial Pressure = 0.293 * 2 = 0.586 atm

5 0
3 years ago
Give two examples of an ionic compound. Chemical name and chemical structure.
Papessa [141]
NaCl (Sodium chloride)
LiF (Lithium fluoride)
4 0
3 years ago
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