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3 years ago

What is the net ionic equation, including phases, for the reaction AgNO3 with K2SO4?

Chemistry

1 answer:

Cerrena [4.2K]3 years ago

6 0

2Ag +(aq) + SO4 2-(aq)------>Ag2SO4 (s)

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. How many milliliters of 0.20 M HCl are needed to exactly neutralize 40. milliliters of 0.40 M KOH

Anuta_ua [19.1K]

Answer:

$V_{HCl}=80mL$

Explanation:

Hello,

In this case, for the given reactants we identify the following chemical reaction:

$KOH+HCl\rightarrow KCl+H_2O$

Thus, we evidence a 1:1 molar ratio between KOH and HCl, therefore, for the complete neutralization we have equal number of moles, that in terms of molarities and volumes become:

$n_{HCl}=n_{KOH}\\\\M_{HCl}V_{HCl}=M_{KOH}V_{KOH}$

Hence, we compute the volume of HCl as shown below:

$V_{HCl}=\frac{M_{KOH}V_{KOH}}{M_{HCl}} =\frac{0.40M*40mL}{0.20M} \\\\V_{HCl}=80mL$

Best regards.

5 0

3 years ago

What happens if energy is added to an energy? what happens if energy is lost in an energy level?

irakobra [83]

Answer:

Please mark me as Brainliest

5 0

2 years ago

Read 2 more answers

A sample of gas occupies 280 mL when the pressure is 560.00 mm Hg . If the temperature remains constant , what is the new pressu

vichka [17]

Answer : The new pressure if the volume changes to 560.0 mL is, 280 mmHg

Explanation :

According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.

$P\propto \frac{1}{V}$

or,

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure = 560.00 mmHg

$P_2$ = final pressure = ?

$V_1$ = initial volume = 280 mL

$V_2$ = final volume = 560.0 mL

Now put all the given values in the above formula, we get:

$560.00mmHg\times 280 mL=P_2\times 560.0 mL$

$P_2=280mmHg$

Therefore, the new pressure if the volume changes to 560.0 mL is, 280 mmHg

3 0

3 years ago

Which reaction has a positive δs°? question 6 options:

Nastasia [14]

B. Because there are 3 molecules in right and 2 molecules in the left, so entropy rises.

3 0

3 years ago

How many moles of liquid water must freeze to remove 100 kJ of heat? (ΔHf = –334 J/ g.

Juliette [100K]

First figure out how many grams must freeze and then convert the grams to moles.
Hf = -334 J/g. Convert this to KJ/g by dividing by 1000. (There are 1000 Joules in a kJ). 
Hf = -334 J/g ÷ 1000 J/kj = -0.334 kJ/g 
Now, divide 100 kJ by -0.334 kJ/g (see how the units are lining up?) 
100 kJ ÷ -0.334 kJ/g = 299 g 
Now convert this to moles by dividing by the molecular weight of water (18.0g/mole). 
299 ÷ 18.0 = 16.6 moles

5 0

3 years ago