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viktelen [127]
3 years ago
11

One of the half-reactions for the electrolysis of water is 2H+(aq) + 2e− → H2(g) If 0.845 L of H2 is collected at 25°C and 782 m

mHg, how many faradays of electricity had to pass through the solution?
Chemistry
1 answer:
DENIUS [597]3 years ago
8 0

0.0725 faradays of electricity had to be passed through the solution.

Explanation:

Find how many hydrogen moles are produced.

1 mole of any gas consumes 24 liters at room temperature  

atmospheric pressure 1 environment is 760 mm Hg  

temperature is 25 deg C  

so if you reduced the pressure down to 760 mm Hg on that 0.845 liters you've gathered, you would discover the volume expanded to  

0.845 x 782/760 = 0.869 liters  

which equals to 0.0362 moles (divide by 24)  

since every atom of hydrogen required 2 electrons to be made, hence we need 0.0725 moles of electrons or 0.0725 faradays.

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The generic metal hydroxide M(OH)2 has Ksp = 8.05×10−12. (NOTE: In this particular problem, because of the magnitude of the Ksp
vodka [1.7K]

Answer:

a. in pure water Solubility (x) = 1.26 x 10⁻⁴M

b. in 0.202M M⁺² Solubility (x) = 9.963 x 10⁻¹²M

The large drop in solubility is consistent with the common ion effect.

Explanation:

a. Solubility in pure water

Given:       M(OH)₂ ⇄ M⁺² + 2OH⁻

            I       ---            0          0

           C      ---             x          2x

           E       ---            x           2x

Ksp = [M⁺²][OH⁻]² = (x)(2x)² = 4x³ => x = CubeRt(Ksp/4)

solubility in pure water = x = CubeRt(8.05 x 10⁻¹²/4) = 1.26 x 10⁻⁴M

b. Solubility in presence of 0.202M M⁺² as common ion.

Given:       M(OH)₂ ⇄       M⁺²      +     2OH⁻

            I       ---            0.202M              0

           C      ---                 +x                 +2x

           E       ---           0.202M + x         2x

                                   ≈ 0.202M

Ksp = [M⁺²][2x]² = (0.202)(2x)² = (0.202)(4x²) = 8.05 x 10⁻¹²

=> x = (8.05 x 10⁻¹²)/(0.202)(4) = 9.963 x 10⁻¹²M

6 0
2 years ago
Two raw materials used in manufacturing of indenouse soap
Trava [24]

Answer:Naoh and animal fats

Explanation:

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8 0
3 years ago
The mode of 12, 17, 16, 14, 13, 16, 11, 14,13, 16 is​
RUDIKE [14]

Answer:

<h2>Mean = 14.2</h2><h2>Median = 14</h2><h2>Mode = 16</h2><h2>Range = 6</h2>

Explanation:

__________________________________________________________

<em>Mean = 14.2 or 14</em>

<em>Median = 14</em>

<em>Mode = 16</em>

<em>Range = 6</em>

<em>__________________________________________________________</em>

<em>Here are all the numbers from least to greatest order: 11, 12, 13, 13, 14, 14, 16, 16, 16, 17.</em>

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8 0
3 years ago
27/13Al+4/2He &gt;&gt;&gt;&gt; 30/15P+
Veseljchak [2.6K]

Answer

Explanation:

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

5 0
3 years ago
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tekilochka [14]

Answer: 0.27621 g

Explanation:

0.297 ml *0.930 g/ml=0.27621 g

8 0
1 year ago
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