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2 years ago

Chemical reactions can be detected by precipitation of a _____ from a solution.

Chemistry

2 answers:

RideAnS [48]2 years ago

7 0

Answer: solid

Explanation: Chemical reactions are those which involve rearrangement of atoms.

Chemical changes are accompanied by following changes:

1) Absorption or release of heat

2) Change in color

3) Formation of gas bubbles

4) Formation of a solid product called as precipitate

Example of formation of precipitate or solid in chemical reaction: $2AgNO_3(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+Ba(NO_3)_2(aq)$

kvv77 [185]2 years ago

5 0

For sure, the answer isn't activation complex because I got that wrong. It is solid.

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A sample of silver with a mass of 63.3 g is heated to a

Irina-Kira [14]

Answer:

The mass of the water in the container is 139.187g

Explanation:

During this process there will not be lost heat. But heat lost of silver is equal to heat won of water

q(lost, silver) = q(gained, water)

-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)

⇒mass of silver = 63.3g

⇒Cpsilver = 0.24J/g °C

⇒initial temperature silver = 384.4 K

⇒ final temperature silver = 292.4 K

⇒mass of water = TO BE DETERMINED

⇒Cpwater = 4.184 J/g °C

⇒initial temperature water = 290.0 K

⇒final temperature = 292.4 K

-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)

-63.3 * 0.24 * (292.4-384.4) = mass * 4.184 * (292.4 - 290.0)

-1397.664 = mass * 0.24 *2.4

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The mass of the water in the container is 139.187g

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3 years ago

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3 years ago

If the fugacity coefficient of the components of a binary mixture are = 0.784, and =0.638 and mole fraction of component 1 is 0.

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Answer : The expression for the fugacity coefficient $\ln \phi$ , for the mixture is, -0.3669.

Explanation : Given,

Fugacity coefficient of component 1 = 0.784

Fugacity coefficient of component 2 = 0.638

Mole fraction of component 1 = 0.4

First we have to calculate the mole fraction of component 2.

As we know that,

$\text{Mole fraction of component 1}+\text{Mole fraction of component 2}=1$

$\text{Mole fraction of component 2}=1-0.4=0.6$

Now we have to calculate the expression for the fugacity coefficient $\ln \phi$ .

Expression used :

$\ln \phi=X_1\ln \phi_1+X_2\ln \phi_2$

where,

$\phi$ = fugacity coefficient

$\phi_1$ = fugacity coefficient of component 1

$\phi_2$ = fugacity coefficient of component 2

$X_1$ = mole fraction of of component 1

$X_2$ = mole fraction of of component 2

Now put all the give values in the above expression, we get:

$\ln \phi=0.4\times \ln(0.784)+0.6\times \ln(0.638)$

$\ln \phi=-0.3669$

Therefore, the expression for the fugacity coefficient $\ln \phi$ , for the mixture is, -0.3669.

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3 years ago