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weqwewe [10]
3 years ago
5

When a gas is Perfect, or Ideal, what properties can be related in an equation?

Chemistry
1 answer:
Snezhnost [94]3 years ago
7 0

Answer:

E.  Density, temperature, and pressure

Explanation:

According to the ideal gas equation ,

P V = n R T

n = number of moles

T = temperature .

R = universal gas constant

P = pressure

V = volume

The formula for density is given by , the mass divided by the volume .

Since , both the equation have , volume in common , hence , both the equations are linked by density .

And the temperature and the pressure are also present in the equation , which can relate to the ideal gas equation .

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Answer:

<em>An object in a fluid medium displaces a set amount of fluid upon immersion. Archimedes' principle states that the weight of the displaced fluid is equal to the buoyant force exerted on the object</em>

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Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas?
Pachacha [2.7K]
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What happens to the energy added during a phase change?
Ivanshal [37]

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Explanation:

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                                             LINK:

https://chemistry.stackexchange.com/questions/82163/clarification-of-kinetic-energy-during-phase-change

7 0
4 years ago
Read 2 more answers
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
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