What is the error? NH4OH (aq) + KOH (aq) --> KOH (aq) + NH4OH (aq)

Chemistry

1 answer:

dexar [7]3 years ago

6 0

Answer:

<u>There is not a chemical reaction. This is just the dissolution of two ionic compounds that remain dissolved in solution, without reacting.</u>

Explanation:

The issue here is that none chemical reaction is happening.

The two compounds mixed are ionic bases: both of them dissociate in water producing OH⁻ ions:

NH₄OH (aq) → NH₄⁺(aq) + OH⁻(aq)

KOH (aq) → K⁺(aq) + OH⁻(aq)

Then, when you write the total ionic equation you have:

NH₄⁺(aq) + OH⁻(aq) + K⁺(aq) + OH⁻(aq) →

NH₄⁺(aq) + OH⁻(aq) + K⁺(aq) + OH⁻(aq)

Look at the species on the reactant side and the product side: the same ions are found on both sides.

That means that all of them are spectator ions: they are just dissolved, and remain in water (aqueous solution) without reacting. None new different compound is formed.

The net ionic equation would not have any species because the spectator ions get canceled.

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Draw the major organic substitution product(s) for (2R,3S)-2-bromo-3-methylpentane reacting with the given nucleophile. Indicate

Andrew [12]

Answer:

(2R,3S)-2-ethoxy-3-methylpentane

and

(2S,3S)-2-ethoxy-3-methylpentane

Explanation:

For this case, we will have $CH_3CH_2O^-$ as nucleophile. Also, this compound is also in excess. So, we will have as solvent $CH_3CH_2OH$ a protic solvent. Therefore the Sn1 reaction would be favored.

The first step would be the carbocation formation followed by the attack of the nucleophile. In this case both isomers would be produced: R and S (see figure).