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Anna007 [38]
3 years ago
8

What is the error? NH4OH (aq) + KOH (aq) --> KOH (aq) + NH4OH (aq)

Chemistry
1 answer:
dexar [7]3 years ago
6 0

Answer:

  • <u>There is not a chemical reaction. This is just the dissolution of two ionic compounds that remain dissolved in solution, without reacting.</u>

Explanation:

The issue here is that none chemical reaction is happening.

The two compounds mixed are ionic bases: both of them dissociate in water producing OH⁻ ions:

  • NH₄OH (aq) → NH₄⁺(aq) + OH⁻(aq)

  • KOH (aq) → K⁺(aq) + OH⁻(aq)

Then, when you write the total ionic equation you have:

NH₄⁺(aq) + OH⁻(aq) +  K⁺(aq) + OH⁻(aq) →

                                                   NH₄⁺(aq) + OH⁻(aq) +  K⁺(aq) + OH⁻(aq)

Look at the species on the reactant side and the product side: the same ions are found on both sides.

That means that all of them are spectator ions: they are just dissolved, and remain in water (aqueous solution) without reacting. None new different compound is formed.

The net ionic equation would not have any species because the spectator ions get canceled.

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3 years ago
Complete the reaction, which is part of the electron transport chain. The abbreviation FMN represents flavin mononucleotide. Use
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Answer:

1. NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂

2. The reactant that is reduced is Q

3. The charge on iron on the right side is +2, Fe²⁺

Explanation:

NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂

The reaction above is catalysed by NADH:ubiquinone oxidoreductase (complex 1), which transfers a hydride ion from NADH to FMN, from which two electrons pass through a series of of Fe-S centers to the iron-sulfur protein N-2. Electron transfer from N-2 to Ubiquinone forms QH₂

The species in a reaction which gains hydrogen irons is reduced,   Therefore, the reactant that is reduced is Q, ubiquinone to form QH₂, ubiquinol.

To determine the oxidation number of iron on the right side of the reaction below,

QH2 + 2cyt c ( Fe3+) ⟶ Q + 2cyt c(Fex) + 2H^+

Sum of charges on the left side = Sum of charges on the right side

Sum of charges on the left side = 2 *+3 = +6

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Therefore the charge on iron on the right side is +2, Fe²⁺

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3 years ago
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