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lara31 [8.8K]
4 years ago
13

A highly polar molecule that contains a weak bond between a hydrogen atom and another element would be

Chemistry
1 answer:
sleet_krkn [62]4 years ago
8 0
A highly polar molecule that contains a weak bond between a hydrogen atom and another element would be a strong acid.
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Transfer 2-3 drops of each solution onto the indicator paper. Be sure to
alexira [117]

Answer:

0.1 M HCl pH: 1-2

0.001 M HCl pH: 3-4

0.00001 M HCl pH: 5-6

Distilled Water pH: 7

0.00001 M NaOH pH: 8-9

0.001 M NaOH pH: 10-11

0.1 M NaOH pH: 12-13

Explanation:

4 0
3 years ago
3. Human activity can cause changes in one of the Earth's systems that lead to subsequent alterations in a different system. For
crimeas [40]

answer: Surface water in nearby areas can become polluted.

Explanation:

8 0
3 years ago
What are three main classifications of the elements
neonofarm [45]

Answer:

Metals, non metals and metalloid

Explanation:

4 0
4 years ago
BEBE
DIA [1.3K]

Reaction 1 : yes

Reaction 2 : no

<h3>Further explanation</h3>

The metal activity series is expressed in voltaic series  

Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

From activity series of Halogen :

F₂>Cl₂>Br₂>I₂

F₂ is the strongest oxidizing agent

1. Reaction

Cl₂ + 2Rbl - 2RbCI+ I₂

Cl₂>I₂⇒reaction can occur⇒yes, reactions will take place.

2. Reaction

I₂ + NiBr₂ - NI₂ + Br₂

Br₂>I₂⇒Reaction can't occur⇒no, reaction will not take place

3 0
3 years ago
2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
azamat

Answer:

K=1.12x10^9

Explanation:

Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

K=\frac{(0.95)^2}{(0.0024)^2(0.00014)}\\\\K=1.12x10^9

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.

Best regards!

4 0
3 years ago
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