If the element have 39 protons, that means that his atomic number is 39, being Yttrium the element. And, the number of protons is the same of the number of electrons, so, 39 electrons.
A) CH4
In general, methane reactions are difficult to control. Partial oxidation to methanol, for example, is a rather difficult reaction because the chemical reactions that occur continue to form carbon dioxide and water even though the amount of oxygen available is insufficient.
<h2>Further explanation
</h2>
Methane is the simplest hydrocarbon in the form of gas with the chemical formula CH4. Pure methane does not smell, but if used for commercial purposes, a bit of sulfur is usually added to detect leaks that might occur.
Methane is a greenhouse gas. Methane is used in chemical industrial processes and can be transported as frozen liquids (liquefied natural gas, or LNG).
Methane is a major component of natural gas, around 87% of volume.
Methane is not toxic, but is highly flammable and can cause explosions when mixed with air.
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Details
Class: college
Subject: chemistry
Keywords: ch4, methane, chemicals
Their lungs would try to expand to about 4 timed the normal volume which would force air into the various body tissues. this can cause a lung expansion injury and it could case air embolism. Air embolism is when air bubbles get trapped in blood vessels. This can lead to a blockage which will could be fatal.
Answer:
chemonoia
Explanation:
Many people have a strong fear of “chemicals” that belies the evidence. It's called chemonoia – and it may be damaging their health. If you were paranoid, you might think there really was something in the water that's damaged our sense of reason.
Stoichiomety:
1 moles of C + 1 mol of O2 = 1 mol of CO2
multiply each # of moles times the atomic molar mass of the compund to find the relation is weights
Atomic or molar weights:
C: 12 g/mol
O2: 2 * 16 g/mol = 32 g/mol
CO2 = 12 g/mol + 2* 16 g/mol = 44 g/mol
Stoichiometry:
12 g of C react with 32 g of O2 to produce 44 g of CO2
Then 18 g of C will react with: 18 * 32/ 12 g of Oxygen = 48 g of Oxygen
And the result will be 12 g of C + 48 g of O2 = 60 g of CO2.
You cannot obtain 72 g of CO2 from 18 g of C.
May be they just pretended that you use the law of consrvation of mass and say that you need 72 g - 18g = 54 g. But it violates the proportion of C and O2 in the CO2 and is not possible.
