Question

Determine the equation for the quadratic relationship graphed below.

Answer 1

Answer:

$\large \boxed{\sf \bf \ \ y=3x^2-6x-1 \ \ }$

Step-by-step explanation:

Hello, please consider the following.

We can read from the graph that the vertex is (1,-4) , it means that the equation is, a being a real number.

$y=a(x-1)^2-4$

And the point (0,-1) is on the graph so we can write.

$a\cdot 1^2-4=-1 \\\\a-4+4=-1+4\\\\a = 3$

So the equation is.

$y=3(x-1)^2-4\\\\=3(x^2-2x+1)-4\\\\=3x^2-6x+3-4\\\\=3x^2-6x-1\\\\=\boxed{3}x^2\boxed{-6}x\boxed{-1}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you