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masya89 [10]
4 years ago
7

100.0 grams of sucrose (C12H22O11)is dissolved in 1.50 L of water. What is the molality?

Chemistry
1 answer:
Nitella [24]4 years ago
8 0

Answer:

Molality = 66.67g/L

Explanation:

Mass of sucrose = 100g

Volume of water = 1.50L

Molality = mass of substance/ volume in L

Molality = 100 / 1.50

Molality = 66.67g/L

Molality of 100g of sucrose in 1.50L of water is 66.67g/L

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Nitrogen has different oxidation states in the following compounds: nitrite ion, nitrous oxide, nitrate ion, ammonia, and nitrog
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To establish the oxidation number of nitrogen in each compound, we know that the sum of the oxidation numbers of the elements is equal to the charge of the species.

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