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marin [14]
3 years ago
14

State three natural conditions under which plasmolysis could occur

Chemistry
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

  1. When the cell is placed in salt solution
  2. When leave celss dry
  3. When cells are placed in sugar solution

Explanation:

Hope this helps

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What is a heterogeneous mixture?​
Setler [38]

Answer:

A heterogeneous mixture is a mixture in which the composition is not uniform throughout the mixture

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3 years ago
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Where does vanillin come from?<br> PLEASE ANSWER
Mila [183]

Answer:

Vanillin, the main flavor component of cured vanilla beans, was synthesized variously from pine bark, clove oil, rice bran, and lignin

Explanation:

5 0
4 years ago
In order to participate in a hydrogen bond, a hydrogen atom must be covalently bonded to one of three elements. What are they?
Lyrx [107]

Oxygen, Nitrogen and Fluorine

Explanation:

In order to participate in a hydrogen bond, a hydrogen atom must be covalently bonded to one of the oxygen, nitrogen and fluorine.

  • Hydrogen bonding is a type of dipole - dipole attraction between two specie.
  • It is an intermolecular force of attraction.
  • This bond type forms when hydrogen is bonded to a more electronegative atom.
  • These atoms are oxygen, nitrogen and fluorine
  • These species draws the electron shared more to themselves and leaves a partial positive charge on the hydrogen and a negative charge on them.
  • The electrostatic force of attraction between the hydrogen of one molecule and the O/N/F of another molecule cause the formation of hydrogen bonds.

learn more:

Hydrogen bonding brainly.com/question/10602513

#learnwithBrainly

5 0
3 years ago
What is the atomic mass of bromine, given the atomic masses and percent abundance of the two isotopes are 78.92 amu (50.7%) and
mojhsa [17]

Answer:

79.9 amu

Explanation:

Given data:

Atomic mass of bromine = ?

Percent abundance of 1st isotope = 50.7%

Atomic mass of 1st isotope = 78.92 amu

Percent abundance of 2nd isotope = 49.3%

Atomic mass of 2nd isotope =80.92 amu

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (50.7×78.92)+(49.3×80.92) /100

Average atomic mass =  4001.24 + 3989.36 / 100

Average atomic mass = 7990.6 / 100

Average atomic mass = 79.9 amu.

6 0
3 years ago
What’s an ionic compound for magnesium and oxide?
malfutka [58]
MgO
{Mg}^{ + 2}  \: and \:   {O}^{ - 2} \\ form \: MgO
4 0
3 years ago
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