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Pani-rosa [81]
3 years ago
10

Cos2x+5sinx=3help????

Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
7 0
Idk. Bbjjjnddsdhjkmnffghnnjjjj
Naddika [18.5K]3 years ago
5 0
76,20..........
That’s my answer.I’m sorry if my answer is wrong
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Que diferencia hay entre drogas estimuladoras depresoras y perturbadoras del sistema nervioso
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Answer:

Las drogas estimulantes son un grupo de medicamentos que tienen un efecto estimulante mental y físico en humanos y animales, estimulando y dando energía al paciente.  Ejemplos de psicoestimulantes son cafeína, efedrina, anfetaminas y metilfenidato.  Estos se usan en pequeñas dosis para, entre otras cosas, mejorar la atención del paciente y la capacidad de planificación, permitiendo un mayor y mejor rendimiento de la persona durante sus actividades diarias.

A su vez, un depresor es una sustancia que paraliza las funciones del sistema nervioso central, siendo las pastillas para dormir y los sedantes los depresores mas comunes. La acción de los sedantes se basa en su capacidad para activar los mediadores del sistema nervioso central, especialmente el ácido gamma-aminobutírico, causando en el paciente una sensación que puede ir desde la tranquilidad y relajación hasta un estado de somnolencia o incluso la propia inducción al sueño.

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3 0
3 years ago
What is the percent composition of dinotrogen pentoxide? With work shown please
iris [78.8K]

Answer:

%N = 25.94%

%O = 74.06%

Explanation:

Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅

We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g

Step 4: Calculate the percent composition  of N₂O₅

We will use the following expression.

%Element = m(Element)/m(Compound) × 100%

%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%

%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%

7 0
3 years ago
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