Answer:
Total of the frequency = The last values of the cumulative frequency (c.f) = 100
Step-by-step explanation:
From the frequency distribution table given in the question, the cumulative frequency (c.f) can be computed by adding each frequency to the sum or total of the preceding frequencies. This makes the last value of the cumulative frequency (c.f) to be equal to the total of the frequency.
Based on this explanation, we have:
<u>mass </u><em><u>m</u></em><u> (kg) </u> <u> frequency </u> <u> mass </u><em><u>m</u></em><u> (kg) </u> <u> c.f </u>
0 < <em>m</em> ≤ 0.1 2 <em> m</em> ≤ 0.1 2
0.1 <<em> m</em> ≤ 0.2 7 <em>m</em> ≤ 0.2 9
0.2 < <em>m</em> ≤ 0.5 32 <em>m</em> ≤ 0.5 41
0.5 < <em>m</em> ≤ 0.8 46 <em>m</em> ≤ 0.8 87
0.8 <<em> m</em> ≤ 1 13 <em>m</em> ≤ 1 100
From the above, we can observe that:
Total of the frequency = 2 + 7 + 32 + 46 + 13 = 100
The last values of the cumulative frequency (c.f) = 100
Therefore, we have:
Total of the frequency = The last values of the cumulative frequency (c.f) = 100
The answer is 420. I hope that it is right and next time use a calculator.<span />
Answer:
∠ BCE = 80°
Step-by-step explanation:
∠ BCD = ∠ ABC = 35° ( alternate angles are congruent )
∠ DCE and ∠ CEF are same- side interior angles and supplementary, thus
∠ DCE + ∠ CEF = 180° , that is
∠ DCE + 135° = 180° ( subtract 135° from both sides )
∠ DCE = 45°
Thus
∠ BCE = ∠ BCD + ∠ DCE = 35° + 45° = 80°
Answer:
D
Step-by-step explanation: