Answer: as the number of predators increases, more prey are captured. as a result the prey population starts to decrease.
Mass = 14.0 g of mercury is formed, 22.6 grams of mercury nitrate, hg(no3)2 reacts with an excess of potassium, k.
An inorganic substance with the formula Hg(NO3)2xH2O is mercury nitrate. Hot, concentrated nitric acid is used to process mercury to create it. By using X-ray crystallography, neither anhydrous nor monohydrate have been verified. The drug might have an impact on the kidneys, peripheral nervous system, and central nervous system. Ataxia, tremors. Given data: Mass of mercury nitrate = 22.17 g, Mass of mercury formed = ?
Solution:
Chemical equation:
Hg(NO₃)₂ + 2K → 2KNO₃ + Hg
Number of moles of mercury nitrate:, Number of moles = mass/molar mass, Number of moles = 22.17 g / 324.6 g/mol, Number of moles = 0.07 mol, Now we will compare the moles of Hg(NO₃)₂ and mercury.
Hg(NO₃)₂ : Hg
1 : 1
0.07 : 0.07
Mass of mercury: Mass = number of moles × molar mass, Mass = 0.07 mol × 200.6 g/mol
Mass = 14.0 g
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Answer:
3.375moles of O₂
Explanation:
The reaction expression is given as;
2KClO₃ → 2KCl + 3O₂
Number of moles of KClO₃ = 2.25moles
Now;
To find the number of moles of O₂ produced we use known number of moles.
So;
2 mole of KClO₃ will produce 3 moles of O₂
2.25moles of KClO₃ will produce 
= 3.375moles of O₂
The amount of Mg(OH)2 present after the reaction is complete is 0.136 moles of Mg(OH)2.
The equation of the reaction is;
2HNO3(aq) + Mg(OH)2(aq) -------> Mg(NO3)2(aq) + 2H2O(l)
Number of moles of Mg(OH)2 = 8.00 g/58 g/mol = 0.138 moles
Number of moles of HNO3 = 0.205 M × 24.2 mL/1000 = 0.00496 moles
Given that;
2 moles of HNO3 reacts with 1 mole of Mg(OH)2
0.00496 moles of HNO3 reacts with 0.00496 moles × 1 mole /2 moles = 0.00248 moles of Mg(OH)2
Hence, Mg(OH)2 is the reactant in excess.
The amount of Mg(OH)2 remaining = Amount present - Amount reacted
Hence; 0.138 moles - 0.00248 moles = 0.136 moles of Mg(OH)2
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3 is trans form 4 is subsection zone and 5is convergent
