The final temperature, t₂ = 30.9 °C
<h3>Further explanation</h3>
Given
24.0 kJ of heat = 24,000 J
Mass of calorimeter = 1.3 kg = 1300 g
Cs = 3.41 J/g°C
t₁= 25.5 °C
Required
The final temperature, t₂
Solution
Q = m.Cs.Δt
Q out (combustion of compound) = Q in (calorimeter)
24,000 = 1300 x 3.41 x (t₂-25.5)
t₂ = 30.9 °C
Answer:
uh A.)? [ZnCI2+H2]? /////////
Answer:
f = 3 × 10⁶ Hz
Explanation:
Given data:
Wavelength of wave = 1.0 ×10² m
Frequency = ?
Solution:
Formula:
Speed of light = wavelength× frequency
Frequency = speed of light / wavelength
speed of light = 3× 10⁸ m/s
f = 3× 10⁸ m/s / 1.0 ×10² m
f = 3 × 10⁶ s⁻¹
s⁻¹ = Hz
f = 3 × 10⁶ Hz
