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Umnica [9.8K]
2 years ago
12

4 possible careers in chemistry and place of application

Chemistry
1 answer:
LenaWriter [7]2 years ago
5 0

Answer:

Analytical Chemist.

Chemical Engineer.

Chemistry Teacher.

Forensic Scientist.

<em>PLZ MARK THE BRAINLIST</em>

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Iron has a density of 7.9 g/cm3. The volume of a regular cylinder is V =πr2h. An iron cylinder has a height of 3.00 m and a mass
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Hfhsnebrjicjcbdnd hope this helps
6 0
2 years ago
What amount of sucrose (C12H22O11) should be added to 5.83 mol water to lower the vapor pressure of water at 50 °C to 72.0 torr?
Triss [41]

Answer:

The amount of sucrose that must be added is 1.66 moles

Explanation:

Colligative property of lowering vapor pressure has this formula:

Vapor pressure of pure solvent (P°) - Vapor pressure of solution = P° . Xm

We have both vapor pressure (pure solvent and solution9, so let's determine the ΔP

ΔP = 92.6 Torr - 72 Torr = 20.6 Torr

Let's add the data in the formula

20.6 Torr = 92.6 Torr . Xm

Xm = Mole fraction of solute → (mol of solute/ mol of solute + mol of solvent)

Mol of solvent = 5.83 mol (data from the problem)

Therefore Xm = 20.6 Torr / 92.6 Torr → 0.222

Let's find out the moles of solute (our unknown value)

0.22 = moles of solute / moles of solute + 5.83 moles of solvent

0.222 (moles of solute + 5.83 moles of solvent) = moles of solute

0.222 moles of solute + 1.29 moles of solvent = moles of solute

1.29 moles of solvent = moles of solute - 0.222 moles of solute

1.29 moles = 0.778 moles of solute

1.29 / 0.778 = moles of solute → 1.66 moles

3 0
3 years ago
List three examples of high energy waves that are harmful to living things:
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UV rays, gamma rays, and x rays
Hope this help
5 0
3 years ago
The force of attraction that holds two atoms together is called a "chemical bond". True or false? if false, what is the right an
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3 years ago
Enter your answer in the provided box. phosphorus pentachloride is used in the industrial preparation of organic phosphorus comp
ankoles [38]
I have a helpful trick for such problems. 

Step 1:
Write the equation asked with exact moles given in question,

                                       PCl₃ + Cl₂   →   PCl₅            --------(1)
Step 2:
Write equations given in data along with energies,

                               P₄ + 6Cl₂     →   4PCl₃       Δ<span>H = −1280 kj  -----(2)
</span>
                               P₄ + 10Cl₂   →   4PCl₅       ΔH<span> = −1774 kj  -----(3)

Step 3:
Compare the equation 1 with eq 2 and 3 and modify eq 2 and 3 according to eq 1 both in terms of reactant and product and number of moles. For example in eq 1 PCl</span>₃ is on left hand side and its number of moles is one, so, modify eq, 2 according to eq 1 both in terms of moles and reactant product sides. i.e.
By inter converting eq 2, the sign of energy will change from negative to positive, and divide eq 2 with 4, to have its ratio's equal to eq 1

                             PCl₃   →   1/4 P₄  +  1.5 Cl₂            ΔH  =  +320 KJ

Same steps are done for eq 3, but in this case signs are not changed only moles are changed

                            1/4P₄ + 2.5Cl₂   →   1/4PCl₅            ΔH = −443.5 kj
Now, 
Compare both last equations,

                             PCl₃   →   1/4 P₄  +  1.5 Cl₂            ΔH  =  +320 KJ


                            1/4P₄ + 2.5Cl₂   →   4/4PCl₅            ΔH = −443.5 kj
                        _____________________________________________

                          PCl₃  +  Cl₂     →     PCl₅                   ΔH = -123.5 KJ
7 0
3 years ago
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