Answer:
1.76cm
Explanation:
We'll begin by calculating the mass of titanium that contain 3.10x10²³ atoms. This can be obtained as follow:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10²³ atoms. This implies that 1 mole of titanium also contains 6.02x10²³ atoms.
1 mole of titanium = 48g
Now, if 48g of titanium contains 6.02x10²³ atoms,
Then Xg of titanium will contain 3.10x10²³ atoms i.e
Xg of titanium = (48x3.10x10²³)/6.02x10²³
Xg of titanium = 24.72g
Next, we shall determine the volume of the titanium. This is illustrated below:
Density of titanium = 4.50g/cm³
Mass of titanium = 24.72g
Volume of titanium =..?
Density = Mass /volume
Volume = Mass /Density
Volume of titanium = 24.72g/4.50g/cm³
Volume of titanium = 5.49cm³
Finally we shall determine the edge length of the titanium cube as follow:
Volume = L³
5.49cm³ = L³
Take the cube root of both side
L = 3√(5.49cm³)
L = 1.76cm
Therefore, the edge length is 1.76cm
