Different amount of species in an area.
Given:
Half life(t^ 1/2) :30 years
A0( initial mass of the substance): 200 mg.
Now we know that
A= A0/ [2 ^ (t/√t)]
Where A is the mass that remains after t years.
A0 is the initial mass
t is the time
t^1/2 is the half life
Substituting the given values in the above equation we get
A= [200/ 2^(t/30) ] mg
Thus the mass remaining after t years is [200/ 2^(t/30) ] mg
The correct Lewis structure of SO2 is the Lewis structure that shows all the 12 valence electrons in the molecule.
A Lewis structure shows the number of valence electrons on the valence shell of all the atoms in a compound. The electrons are shown as dots around the symbol of each element or a dash to indicate shared electrons in a covalent bond.
Looking at the Lewis structure of SO2 attached to this answer, we can see the twelve valence electrons in the molecule and how they are distributed around each atom as shown.
Learn more: brainly.com/question/20514601