Answer:
true
Explanation:
Gravity (or the acceleration due to gravity) is 9.81 meters per second squared, on the surface of Earth, because of the size of Earth and the distance we are on its surface from its center.
Answer:
![M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right]](https://tex.z-dn.net/?f=M%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dcos%20%5C%2060%260%5C%5C0%26-sin%20%5C%2060%5Cend%7Barray%7D%5Cright%5D)
Explanation:
To find the matrix, let's decompose the vectors, the rotated angle is (-60C) for the prime system
x ’= x cos (-60)
y ’= y sin (-60)
we use
cos 60 = cos (-60)
sin 60 = - sin (-60)
we substitute
x ’= x cos 60
y ’= - y sin 60
the transformation system is
x '
the transformation matrix is
![M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right]](https://tex.z-dn.net/?f=M%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dcos%20%5C%2060%260%5C%5C0%26-sin%20%5C%2060%5Cend%7Barray%7D%5Cright%5D)
Answer:
(a) 0.075
(b)20.1 mA
(c) 2.412 W
Explanation:
Vs = 9 V, is = 268 mA = 0.268 A
Vp = 120 V
(a) Let the number of turns in primary coil is Np and the number of turns in secondary coil of the transformer is Ns.
Ns / np = Vs / Vp
Ns / Np = 9 / 120
Ns / Np = 3 : 40 = 0.075
(b) Let the current drawn from the wall socket is ip.
Ns/ Np = ip / is
0.075 = ip / 0.268
ip = 0.0201 A = 20.1 mA
(c) Power delivered by the socket = Vp x ip = 120 x 0.0201 = 2.412 W
Power sent to the batteries = Vs x is = 9 x 0.268 = 2.412 W