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Aneli [31]
3 years ago
11

A net force of 500 N acts on a 100 kg cart. What is the acceleration of the cart if the mass is doubled?

Physics
1 answer:
oksian1 [2.3K]3 years ago
8 0

Answer:

2.5 m/s²

Explanation:

You can solve the following equation: F=ma for acceleration.

You'll be left with this:

a=F/m

And then you substitute the force and the doubled mass

a=500N/200kg

a=2.5 m/s²

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What is the resultant force acting on an object? The first force is 45 N West and the second is 23 N East.
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Answer:

22N West

Explanation:

45-23 because they are in opposite directions.

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Jennifer runs 5 miles east, then stops to take a break. after her break, she continues running 4 more miles east. what is her di
andreev551 [17]

Jennifer runs 5 miles east, then stops to take a break. after her break, she continues running 4 more miles east.

In this the total distance she covers is 9 miles and the total displacement is also the same as the distance that is 9 miles.

<h3>What is the difference between distance and displacement?</h3>

Displacement is the shortest distance between initial and final position, or we can say it is the straight-line distance between initial and final position.

Whereas distance is considered as the total path length covered from initial position till the final position. The Displacement of a body is always less than or equal to the distance.

Displacement can be zero in case the initial and final positions coincide, but distance can never be zero.

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cestrela7 [59]
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3 years ago
What is the purpose of experimentation in a research study
Nat2105 [25]
Hello,

The answer is to "prove your hypothesis".

Reason:

Researchers do experiments to prove there hypothesis they will most likely do the experiment a few times in older to have the conclusion valid therefore proving his or her experiment. 

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
6 0
3 years ago
Read 2 more answers
A 35-mm single lens reflex (SLR) digital camera is using a lens of focal length 35.0 mm to photograph a person who is 1.80 m tal
olganol [36]

Answer:

a) 35.44 mm

b) 17.67 mm

Explanation:

u = Object distance =  3.6 m

v = Image distance

f = Focal length = 35 mm

h_u= Object height = 1.8 m

a) Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{35}-\frac{1}{3600}\\\Rightarrow \frac{1}{v}=\frac{713}{25200} \\\Rightarrow v=\frac{25200}{713}=35.34\ mm

The CCD sensor is 35.34 mm from the lens

b) Magnification

m=-\frac{v}{u}\\\Rightarrow m=-\frac{35.34}{3600}

m=\frac{h_v}{h_u}\\\Rightarrow -\frac{35.34}{3600}=\frac{h_v}{1800}\\\Rightarrow h_v=-\frac{35.34}{3600}\times 1800=-17.67\ mm

The person appears 17.67 mm tall on the sensor

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3 years ago
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