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3 years ago

A net force of 500 N acts on a 100 kg cart. What is the acceleration of the cart if the mass is doubled?

Physics

1 answer:

oksian1 [2.3K]3 years ago

8 0

Answer:

2.5 m/s²

Explanation:

You can solve the following equation: F=ma for acceleration.

You'll be left with this:

a=F/m

And then you substitute the force and the doubled mass

a=500N/200kg

a=2.5 m/s²

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Consider the following three statements: For any electromagnetic radiation, the product of the wavelength and the frequency is a

boyakko [2]

Answer:

The correct answer is B. Statements (i) and (ii) are true.

Explanation:

Fisrt statement:

Electromagnetic radiation such as wave, wavelength λ and oscillation frequency ν are related by a constant, the speed of light. The equation is given by:

$c= \lambda \nu$

So the first statement is true.

Second statement:

$c=\lambda \nu\\c= 3.0 A \times 1.0\times 10^{18} Hz\\c= 3.0\times 10^{-10} m \times 1.0\times 10^{18} s^{-1}\\c=3\times 10^8 \frac{m}{s}$

The value of c in the vacuum is 3×10⁸ m/s. Hence, the second statement is true.

Third statement:

The speed of any electromagnetic radiation is constant regardless the type of radiation.

Hence, the third statement is false.

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3 years ago

The eficiency of a simple machine can never be 100% why?

Kitty [74]

Answer:

Systems always tend toward a state of decreasing order unless more energy is provided into the system to counteract this tendency.

6 0

3 years ago

What is the mechanical energy of a 500kg rollercoaster car moving with a speed of 3m/s at the top hill that is 30m high

koban [17]

K.E = 1/2*m*v^2 = 1/2(500)(3)^2 = 2250 J

m*g*h = 500(9.8)(30) = 147000 J

2250 + 147000 = 149250

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3 years ago

A 70.0 kg ice hockey goalie, originally at rest, has a 0.110 kg hockey puck slapped at him at a velocity of 31.5 m/s. Suppose th

NISA [10]

Answer

given,

mass of the goalie(m₁) = 70 kg

mass of the puck (m₂)= 0.11 kg

velocity of the puck = 31.5 m/s

elastic collision

$v_1=\dfrac{m_2-m_1}{m_1+m_2}v_1+\dfrac{2m_2}{m_1+m_2}v_2$

$v_{pf}=\dfrac{0.11-70}{0.11+70}31.5+\dfrac{2m_2}{m_1+m_2}\times (0)$

$v_{pf}=-31.4\ m/s$

$v'_2 = \dfrac{2m_1v_1}{m_1+m_2}-\dfrac{(m_2-m_1)v_2}{m_2+m_1}$

$v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}-\dfrac{(0.11-70)\times 0}{m_1+m_2}$

$v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}$

$v_{gf} = 0.0988\ m/s$

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3 years ago

Ball A Mass: 0.45 kg Velocity: 50 m/s Ball B Mass: 0.45 kg Velocity: 80 m/s Ball C Mass: 0.45 kg Velocity: 25 m/s Which ball has

charle [14.2K]

Definition formula for momentum: P = mv

So P(A) = 0.45 * 50 = 22.5 kgm/s

P(B) = 0.45 * 80 = 36 kgm/s

P(C) = 0.45 * 25 = 11.25 kgm/s

B has the greatest momentum

4 0

4 years ago

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