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Aneli [31]
2 years ago
11

A net force of 500 N acts on a 100 kg cart. What is the acceleration of the cart if the mass is doubled?

Physics
1 answer:
oksian1 [2.3K]2 years ago
8 0

Answer:

2.5 m/s²

Explanation:

You can solve the following equation: F=ma for acceleration.

You'll be left with this:

a=F/m

And then you substitute the force and the doubled mass

a=500N/200kg

a=2.5 m/s²

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The muscular system brings what to the body?
kow [346]
The muscular system brings strength and endurance to the body. It helps us perform everyday activities. As well as soaks up water to keep us hydrated longer.
6 0
3 years ago
The initial speed of a body is 7.1 m/s. What is its speed after 2.23 s if it accelerates uniformly at 2.64 m/s 2 ? Answer in uni
Nana76 [90]

13.0m/s

1.2m/s

Explanation:

Given parameters:

Initial speed of the body = 7.1m/s

time taken = 2.23s

Acceleration = 2.64m/s²

Unknown:

Final speed = ?

Solution:

Acceleration is the rate of change of velocity with time.

   a = \frac{V - U}{T}

a  = acceleration

V = final speed

U = initial speed

T = time taken

  Input the variables and solve for V;

 

   2.64 = \frac{V - 7.1}{2.23}  

  V - 7.1 = 5.9                              expression 1

  V = 5.9 + 7.1 = 13.0m/s

B

Using the same parameters, the speed after a uniform deceleration of -2.64m/s², the negative sign implies deceleration;

 from expression 1;

           V - 7.1  = -5.9

           V = -5.9 + 7.1 = 1.2m/s

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

5 0
3 years ago
What current flows through a 2.56-cm-diameter rod of pure silicon that is 20.0 cm long, when 1.00 ✕ 103 V is applied to it? (Suc
vfiekz [6]

Answer:

Current, I = 0.0011 A

Explanation:

It is given that,

Diameter of rod, d = 2.56 cm

Radius of rod, r = 1.28 cm = 0.0128 m

The resistivity of the pure silicon, \rho=2300\ \Omega-m

Length of rod, l = 20 cm = 0.2 m

Voltage, V=1\times 10^3\ V

The resistivity of the rod is given by :

R=\rho\dfrac{L}{A}

R=2300\ \Omega-m\dfrac{0.2\ m}{\pi (0.0128\ m)^2}

R = 893692.30 ohms

Current flowing in the rod is calculated using Ohm's law as :

V = I R

I=\dfrac{V}{R}

I=\dfrac{10^3\ V}{893692.30\ \Omega}

I = 0.0011 A

So, the current flowing in the rod is 0.0011 A. Hence, this is the required solution.

6 0
3 years ago
Answer plz also give reason
user100 [1]

See this suggested solution.

1. Let a force F' is the vector sum of the forces P and Q, then it is shown on the attached picture and marked with red color.

2. according to the condition the force F holds the object, then F should have the same length as the force F' and the opposite direction.

3. using the conditions described in 2. the answer is C.

4 0
3 years ago
An observer that moves with an electrical charge senses:
Shtirlitz [24]

Here observer is moving along with an electrical charge

now magnetic field on a moving charge is given by equation

F = qvB sin\theta

electrical force on a moving charge is given by formula

F = qE

so here we can say when observer is moving with the charge it will have two forces on it

1. magnetic force due to existing magnetic field

2. electric force due to electric field

so here he must have to experience both type of field presence

So here correct answer must be

<em>C- electric and magnetic fields </em>

3 0
3 years ago
Read 2 more answers
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