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gladu [14]
3 years ago
9

Which of the following is the best reason that scientific models are used? (1 point)

Physics
2 answers:
marshall27 [118]3 years ago
7 0
B they help visualize things that are very complex, very large, or very small.
sdas [7]3 years ago
3 0

Answer:

hi there!

Explanation:

B They help visualize things that are very complex, very

large, or very small.

Possible answers include three-dimensional representations of microscopic objects, computer simulations of weather patterns, small-scale representations of rockets and airplanes, and graphs derived from collecting scientific data. Scientific models are used to gain a better understanding of systems and processes.

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One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large
Eva8 [605]

Answer:

6666.67 Newtons

Explanation:

The formula F=ma (force is equal to mass multiplied by acceleration) can be used to calculate the answer to this question.

In this case:

  • mass= 0.1mg= 1*10^-7 kg
  • velocity= 4.00*10^3 m/s
  • time= 6.00*10^-8 s

Using velocity and time, acceleration can be calculated as:

  • a= 6.667*10^10 m/s²

Substituting these values into the formula F=ma, the answer is:

  • F= (1*10^-7)kg * (6.667*10^10) m/s²
  • F= 6666.67 Newtons of force
5 0
3 years ago
An object has a 600 N force pushing it to the right, while a 700 N force pushes in the opposite direction. Gravity also acts on
nordsb [41]
Left is the answer 3
6 0
3 years ago
Read 2 more answers
What is the velocity of the object?
dmitriy555 [2]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2 /><h2>\huge\boxed{\text{V = 9.5 m/s}}</h2><h2>_____________________________________</h2>

<h2>DATA:</h2>

mass = m = 2kg

Distance = x = 6m

Force = 30N

TO FIND:

Work = W = ?

Velocity = V = ?

<h2>SOLUTION:</h2>

According to the object of mass 2 kg travels a distance when the force was exerted on it. The graph between the Force and position was plotted which shows that 30 N of force was used to push the object till the distance of 6.0m.

To find the work, I will use the method of determining the area of the plotted graph. As the graph is plotted in the straight line between the Force and work, THE PICTURE ATTCHED SHOWS THE AREA COVERED IN BLUE AS WORK DONE AND HEIGHT AS 30m AND DISTANCE COVERED AS 6m To solve for the area(work) of triangle is given as,

{\Longrightarrow}\qquad \qquad \qquad W\ =\ \frac{1}{2}\;(Base)\:(Height)

Base is the x-axis of the graph which is Position i.e. 6m

Height is the y-axis of the graph which is Force i.e. 30N

So,

                           W\ =\ \frac{1}{2}\:6\:x\:30

                           W   =  90 J

The work done is 90 J.

According to the principle of work and kinetic energy (also known as the work-energy theorem) states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.

{\Longrightarrow}\qquad \qquad \qquad W\quad =\quad K.E\\\\{\Longrightarrow}\qquad \qquad \qquad W\quad =\quad \frac{1}{2}\ m\ V^2 \\\\{\Longrightarrow}\qquad \qquad \qquad W\quad =\quad \frac{1}{2}\ 2\ (V_f-V_i)^2\\\\{V_i\ is\ 0\ because\ the\ object\ was\ initially\ at\ rest}\\\\ {\Longrightarrow}\qquad \qquad \qquad W\quad\ =\ \frac{1}{2}\ x\ 2\ (V_f-0)^2 \\\\{\Longrightarrow}\qquad \qquad \qquad 90\quad = \frac{1}{2}\ x\ 2\ (V_f)^2

\\\\{\Longrightarrow}\qquad \qquad \qquad V_f\quad =\ \sqrt{\frac{2\ (90)\ }{2}}\\\\{\Longrightarrow}\qquad \qquad \qquad \boxed {V_f\quad =\ 9.48\ m/s}

\boxed{The\ Velocity\ of\ the\ Object\ of\ mass\ 2kg\ at\ 6\ meters\ of\ distance\ was\ 9.48\ m/s}

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

8 0
3 years ago
Review
sleet_krkn [62]

Answer:

yes

Explanation:

8 0
4 years ago
Read 2 more answers
Problem 3.2 Part A Draw the vector C⃗ =A⃗ +B⃗ .(Figure 1)
Elodia [21]
I can't answer this question without a figure. I've found a similar problem as shown in the first picture attached. When adding vectors, you don't have to add the magnitudes only, because vectors also have to factor in the directions. To find the resultant vector C, connect the end tails of the individual vectors. <em>The red line (second picture) represents the vector C.</em>

5 0
3 years ago
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