Answer:
NE DIYON INGILIZ MISIN SEN
 
        
             
        
        
        
Answer:
34 m/s
Explanation:
Potential energy at top = kinetic energy at bottom + work done by friction
PE = KE + W
mgh = ½ mv² + Fd
mg (d sin θ) = ½ mv² + Fd
Solving for v:
½ mv² = mg (d sin θ) − Fd
mv² = 2mg (d sin θ) − 2Fd
v² = 2g (d sin θ) − 2Fd/m
v = √(2g (d sin θ) − 2Fd/m)
Given g = 9.8 m/s², d = 150 m, θ = 28°, F = 50 N, and m = 65 kg:
v = √(2 (9.8 m/s²) (150 m sin 28°) − 2 (50 N) (150 m) / (65 kg))
v = 33.9 m/s
Rounded to two significant figures, her velocity at the bottom of the hill is 34 m/s.
 
        
             
        
        
        
Answer:
<h3>The answer is 2.51 s</h3>
Explanation:
The time taken can be found by using the formula

d is the distance
v is the velocity
From the question we have

We have the final answer as
<h3>2.51 s</h3>
Hope this helps you
 
        
             
        
        
        
Answer:
The frictional torque is 
Explanation:
From the question we are told that 
    The mass attached to one end the string is 
    The mass attached to the other end of the string is  
     The radius of the disk is  
At equilibrium the tension on the string due to the first mass is mathematically represented as 
       
substituting values 
       
       
At equilibrium the tension on the string due to the  mass is mathematically represented as 
       
      
       
The  frictional torque that must be exerted is mathematically represented as 
       
substituting values  
      
      