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3 years ago

Components of crude oil can be separated through a process called _____.

Chemistry

1 answer:

Drupady [299]3 years ago

3 0

Answer:

Components of crude oil can be separated through a process called fractional distillation.

Explanation:

Fractional distillation can be described as a method of distillation in which a liquid mixture is separated based on the different boiling points of the components present in the mixture. The components of crude oil have different boiling temperatures hence, they can be separated by the process of fractional distillation.

The fractionating column has high temperatures at the bottom so components with high temperatures are separated at the bottom. The upper columns have lower temperatures. Components with lower boiling temperatures get separated at the upper columns.

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Calculate the mass of water formed when 4g of methane is burnt in excess oxygen

wariber [46]

Answer:

Mass of water formed: 9g

Explanation:

Hope it helps you!

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2 years ago

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algol [13]

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7 0

2 years ago

A 2 L container contains 5 moles of helium gas at 0.5 atm. What is the temperature of the gas?

lara [203]

Answer:

2.44 K IS THE TEMPERATURE OF THE GAS

Explanation:

PV = nRT

P = 0.5 atm

V = 2 L

n = 5 moles

R = 0.082 L atm mol^-1 K^-1

T = ?

Substituting for T in the equation, we obtain:

T = P V / nR

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7 0

3 years ago

Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /

barxatty [35]

Answer:

$[Pb^{2+}]=3.9 \times 10^{-2}M$

this is the concentration required to initiate precipitation

Explanation:

$PbCl_2$ ⇄ $Pb^{2+}+2Cl^-$

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

$Ip=[Pb^{2}][2Cl^-]^2=Ksp$

$Ksp=2.4\times 10^{-4}$

lets solubility=S

$[Pb^{2+}] = S$

$[Cl^-]=2S$

$Ksp=[Pb^{2+}]\times [Cl^-]^2$

$Ksp=S \times (2S)^2$

$Ksp=4S^3$

$S=\sqrt[3]{\frac{Ksp}{4} }$

$S=3.9\times 10^{-2}$

$[Pb^{2+}]=3.9 \times 10^{-2}M$ this is the concentration required to initiate precipitation

4 0

3 years ago

Which bond has the greatest ionic character? A) H-Cl B) H-F c) H-O d) H-N

Len [333]

I really hope that this helps. H-F because the difference in electronegativity is the greatest, about 1.9 on the Pauling scale. The term means which bond has the greatest polarity and is thus most similar to an ionic bond, which involves the transfer of an electron (in opposition to covalent bonds, which share electrons). It is H-F because out of all the atoms here bonded with H, ie hydrogen, F is the most electronegative which means it can pull the bonded electrons to itself more than can Cl, O, and N. That means a stronger polarization of the electron cloud forming the bond with hydrogen and therefore a stronger ionic character.

5 0

3 years ago