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3 years ago

8

Is the sky actually blue?

1 answer:

Mkey [24]3 years ago

8 0

Answer:

When we look at an arbitrary point in the sky, away from the sun, we see only the light that was redirected by the atmosphere into our line of sight. Because that occurs much more often for blue light than for red, the sky appears blue. Violet light is actually scattered even a bit more strongly than blue.

Explanation:

You might be interested in

How many seconds does it take to deposit 0.94 g of Ni on a decorative drawer handle when 14.9 A is passed through a Ni(NO3)2 sol

Goshia [24]

Answer:

Time take to deposit Ni is 259.02 sec.

Explanation:

Given:

Current $I = 14.9$ A

Faraday constant $= 96485$ $\frac{C}{mole}$

Molar mass of Ni $= 58.69$ $\frac{g}{mole}$

Mass of Ni $= 0.94$ g

First find the no. moles in Ni solution,

Moles of Ni $= \frac{0.94}{58.69}$

$= 0.02$ mol

From the below reaction,

$Ni^{2+} + 2e$ ⇆ $Ni_{(s)}$

Above reaction shows "1 mol of $Ni^{2+}$ requires 2 mol of electron to form 1 mol of $Ni_{(s)}$ "

So for finding charge flow in this reaction we write,

$=$ $0.02 \times \frac{2 }{1 } \times 96485 \frac{C}{mol}$

Charge flow $= 3859.4$ C

For finding time of reaction,

$I = \frac{q}{t}$

Where $q =$ charge flow

$t = \frac{q}{I}$

$t = \frac{3859.4}{14.9}$

$t = 259.02$ sec

Therefore, time take to deposit Ni is 259.02 sec.

3 0

3 years ago

The mass number is equal to which of the following? Question 5 options: Protons + Neutrons Protons + Atomic Number Neutrons + El

Sedbober [7]

Answer: The mass number is the sum of the numbers of protons and neutrons present in the nucleus of an atom.

I hope that this helps you !

7 0

3 years ago

2.5 piece of lithium is dropped into a 500 g sample of water at 22.1 C.ten temperature of the water increases to 23.5 C. How muc

Dominik [7]

Answer:

2.6 kJ

Explanation:

The formula for the amount of heat (q) absorbed by the water is

q = mCΔT

1. Calculate ΔT

ΔT = 23.5 °C - 22.1 °C = 1.4 °C

2. Calculate q

q₂ = mCΔT = 500 g × 4.184 J·°C⁻¹g⁻¹ × 1.4 °C = 2900 J = 2.9 kJ

3 0

4 years ago

A football is inflated to 12psi at 20°C What is the new pressure in the football

Radda [10]

Answer: The new pressure is 3 psi.

Explanation:

Given: $P_{1}$ = 12 psi, $T_{1} = 20^{o}C$

$P_{2}$ = ?, $T_{2} = 5^{o}C$

Formula used is as follows.

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{12 psi}{20^{o}C} = \frac{P_{2}}{5^{o}C}\\P_{2} = \frac{12 psi \times 5^{o}C}{20^{o}C}\\= 3 psi$

Thus, we can conclude that the new pressure is 3 psi.

7 0

3 years ago

For the main group elements( excluding the transition elements) , is it necessary to memorize the type of ion each element makes

ella [17]

You can predict it based of the electronegativity

7 0

3 years ago