Answer:
The height of the cliff is 28.57 m.
Explanation:
Given;
initial velocity of the rock, u = 12.6 m/s
time of motion, t = 1.45 s
The height of the cliff is given by;
h = ut + ¹/₂gt²
h = (12.6 x 1.45) + ¹/₂(9.8)(1.45)²
h = 18.27 + 10.30
h = 28.57 m
Therefore, the height of the cliff is 28.57 m.
Answer:
Explanation:
In this case we will use the Bohr Atomic model.
We have that:
We can calculate the centripetal force using the coulomb formula that states:
Where K=
and r is the distance.
Now we can say:
The mass of the electron is = Kg
The charge magnitud of an electron and proton are=
Substituting what we have:
[/tex]
so:
Kepler's 3rd law
p^2 = 5.2 ^3
p^2 = 140.608
p = 11.857
Hope this helps