Complete Question:
A hollow cylinder with an inner radius of 4.0mm and an outer radius of 30mm conducts a 3.0-A current flowing parallel to the axis of the cylinder. If the current density is uniform throughout the wire, what is the magnitude of the magnetic field at a point 12mm from its center?
Answer:
The magnitude of the magnetic field = 7.24 μT
Explanation:
Inner radius, a = 4.0 mm = 0.004 m
Outer radius, b = 30 mm = 0.03 m
Radius, r = 12 mm = 0.012 m
let h² = b² - a²
h² = 0.03² - 0.004²
h² = 0.000884
Let d² = r² - a²
d² = 0.012² - 0.004²
d² = 0.000128
Current I = 3A
μ = 4π * 10⁻⁷
The magnitude of the magnetic field is given by:
B = 7.24 * 10⁻⁶T
B = 7.24 μT
A defective protein would be produced leading to either that protein cell being killed or developing into a cancer
The answers are as follows;
a) the inductive reactance is 322 ohm
b) The maximum voltage is 387.5 V
c) The rms and maximum currents in the inductor are 1.2 A and 0.85 A.
<h3>What is the reactance?</h3>
The reactance is obtained from;
XL = 2πfL
XL = 2 * 3.14 * 57.0 * 0.900
XL = 322 ohm
The maximum voltage is obtained as;
Vo = Vrms * √2
Vo = 274 V * √2
Vo = 387.5 V
Io = Vo/XL
Io = 387.5 V/ 322 ohm
Io = 1.2 A
Irms = 274 V/322 ohm
Irms = 0.85 A
Learn more about inductive reactance:brainly.com/question/17129912
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Answer:
7
g/cm³
Explanation:
The formula for density is 
. Let's apply the formula to the question:
= 7g/cm³
Answer:
80,886 cm^3
Explanation:
v= lwh (also known as length × width × height)
v = 122cm × 51cm × 13cm
v = 80,886 cm^3
