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Artemon [7]
3 years ago
15

Is hydrogen energy renwable? Why How is it used nowadays How is it obtained?

Physics
1 answer:
hram777 [196]3 years ago
5 0

Answer:

t

Explanation:

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A point charge (–5.0 µC) is placed on the x axis at x = 4.0 cm, and a second charge (+5.0 µC) is placed on the x axis at x = –4.
AveGali [126]

Answer:

The magnitude of electric force is  7.2\times10^{-3} N

Explanation:

Coulomb's Law:

The force of attraction or repletion is

  • directly proportional to the products of charges i.e F\propto q_1q_2
  • inversely proportional to the square of distance i.e F\propto \frac{1}{r^2}

\therefore F\propto \frac{q_1q_2}{r^2}

\Rightarrow F=k \frac{q_1q_2}{r^2}    [ k is proportional constant=9×10⁹N m²/C²]

There are two types of force applied on Q=+2.5 μC=2.5×10⁻⁶ C

Let F₁ force be applied on Q =+2.5 μC by q₁= -5.0 μC = - 5.0×10⁻⁶ C

and F₂ force  be applied on Q=+2.5 μC by q₂= 5.0 μC= 5.0×10⁻⁶ C

Since the magnitude of F₁ and F₂ are same. Therefore their y component cancel.

If we draw a line from q₁ to Q .

The it forms a triangle whose base = 4.0 cm and altitude =3.0 cm.

Let hypotenuse = r

Therefore, r=\sqrt{altitude^2+base^2} =\sqrt{3^2+4^2} =5

we know,

cos \theta = \frac{base }{hypotenuse}

\Rightarrow cos \theta = \frac{4 }{r}

Total force F_Q = 2.F_1 cos\theta \hat{i}

                         =2k\frac{Qq_1}{r^2} cos\theta \hat i

                         =2\ \frac{9\times1 0^9\times2.5 \times 5\times 10^{-12}}{r^2} \frac{4}{r} \hat i

                         =8\ \frac{9\times10^9\times2.5 \times 5\times 10^{-12}}{5^3} \hat i     [ r=5]

                         =7.2\times10^{-3}\hat i   N

The magnitude of electric force is  7.2\times10^{-3} N

                         

3 0
3 years ago
Consider a uniformly charged sphere (an insulating sphere of radius R) and a spherical Gaussian surface with radius R 2 concentr
vodomira [7]

Answer:

Joe Mama

Explanation:

Reason? Joe mama half of her torso is radius u want to find......

5 0
3 years ago
A car travels with an average speed of 22 m/s.what is this speed in km/s
Debora [2.8K]
It is .022 kilometers.
4 0
4 years ago
Read 2 more answers
a person with a mass of 75kg jumps on the trampoline the trampoline creates a fprce of 375n on them what is the acceleration of
Anarel [89]

Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:

            -4.8 m / s²

Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body

            F = m a

Where the bold letters indicate vectors, F is the force, m the masses and the acceleration

The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system

 

               F_t -W = m a

Whera F_t is the trampoline force

Body weight is

                W = mg

We substitute

              F_t - mg = ma

              a =\frac{F_t - m g}{m}

Let's calculate

              a = \frac{375 - 75 \ 9.8 }{75}

              a = -4.8 m / s²

The negative sign indicates that the acceleration is directed downward.

In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is

            -4.8 m / s²

Learn more here:  brainly.com/question/19860811

7 0
3 years ago
Gravitational force is affected by: a. mass c. distance b. weight d. both a and c
NikAS [45]
<span>Gravitational force is affected by: a. mass c. distance b. weight d. both a and c

Mass.

</span>When an object is above the Earth's surface it hasgravitational potential<span> energy (GPE). The amount of GPE an object has depends on its mass and its height above the Earth's surface</span><span>


</span>
6 0
4 years ago
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