Is hydrogen energy renwable? Why<br> How is it used nowadays<br> How is it obtained?

However, had it been a real sound, the sound's pitch would have been increased by the Doppler Effect, since the Falcon was movin

kkurt [141]

I believe the answer is C.

3 0

3 years ago

Read 2 more answers

What is the gravitational field strength at a distance of 60.0 km above the surface of the earth

zloy xaker [14]

Answer:

g=9.64m/s^2.

Explanation:

Gravitational field strength (in other words, gravitational acceleration) is given as follows:g=GMR2g=R2GMwhere G=6.674×10−11m3kg⋅s2G=6.674×10−11kg⋅s2m3 is the gravitational constant, M=5.972×1024kgM=5.972×1024kg is the mass of the Earth, and R=6.371×106m+0.06×106m=6.431×106mR=6.371×106m+0.06×106m=6.431×106m is the distance from the center of the Earth to the required point above the surface (radius plus 60 km).

6 0

2 years ago

How does urban planning impact land?

pochemuha

Answer:

Ensures land is used for its designated purposes hence avoiding misuse of land.

Explanation:

The process of urban planning ensures that different land uses are shown such as commercial, residential, public land, forestry and agricultural and institutional lands. This process helps in designing for essential services such as roads, sewarage and water, gas and electricity. In the process, encroachment is controlled and land utilized as planned. Therefore, land is properly utilized while minimizing environmental pollution, leading to sustainable development.

4 0

4 years ago

Complex matching suggests that individuals who have formed a relationship may differ predominantly in the area of __________.

jek_recluse [69]

Answer:

physical attractiveness

Explanation:

7 0

3 years ago

"If the object has a speed of" -2.5 m/s at x = 0m, find its speed at x = 5.00 m and its speed at x = 15.0 m.

frez [133]

Answer:

Hello your question has some missing parts attached below is the missing part

A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below.

answer : speed at x = 5 m = 3.35 m/s

speed at x = 15m = 5.12 m/s

Explanation:

initial speed( x = 0 ) = 2.5 m/s

speed at x = 5.00 m = ?

speed at x = 15 m = ?

Determine speed at x = 5 m

First we will apply the expression for work-energy theorem

w = $\frac{1}{2} m(v^2 - v_{0}^2 )$ ----- ( 1 )

where : w = 7.50J, $v_{0}$ = 2.5m/s , m = 3.0 kg ( in the expression of work )

input values into equation 1

7.50 = 1/2 (3 ) ( v^2 - 2.5^2 )

7.50 = 3/2 ( v^2 - 6.25 )

5 j/kg = v^2 - 6.25

∴ v = √11.25 = 3.35 m/s

Determine speed at X = 15

first we will determine the work done form x = 5 to x = 15

W = 7.5J + 15J + 7.5J = 30J, $v_{0}$ = 2.5m/s , m = 3.0 kg

w = $\frac{1}{2} m(v^2 - v_{0}^2 )$ --- ( 2 )

equation2 becomes

30J = 1/2 ( 3 ) ( v^2 - 6.25 )

30J = 3/2 ( V^2 - 6.25 )

20 J/kg = v^2 - 6.25

v = √26.25 = 5.12 m/s

5 0

3 years ago

Is hydrogen energy renwable? Why How is it used nowadays How is it obtained?