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sertanlavr [38]
3 years ago
12

A person measures his or her heart rate by counting the number of beats in 30s. If 40±1 beats are counted in 30.0±0.5s, what is

the heart rate and its uncertainty in beats per minute?
Physics
1 answer:
nordsb [41]3 years ago
7 0

Answer:

Rate = 1.33 \pm 0.055 beats per second

Explanation:

Number of heart beats = 40 \pm 1

time taken = 30.0 \pm 0.5 s

now we have

N = 40 \pm 2.5%

t = 30.0 \pm 1.67%

now rate of heart beat is defined as number of heart beat per unit of time

so we have

Rate = \frac{N}{t}

Rate = \frac{40 \pm 2.5}{30 \pm 1.67}

so we have

Rate = 1.33 \pm (2.5 + 1.67 )

Rate = 1.33 \pm 4.17%

Rate = 1.33 \pm 0.055 beats per second

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