Answer:
= 8
Explanation:
noise from power mower = 106 dB
noise from rock concert = 115 dB
we would be applying the formula for the decibel level of sound to get the intensities.
(B) = 10 log \frac{I}{I₀}
I = intensity of sound
I₀= reference intensity = 10^{-12} W/m^{2}
- intensity of the power mower
106 = 10 log \frac{I}{10^{-12}}
10.6 = log \frac{I}{10^{-12}}
10^{10.6} = \frac{I}{10^{-12}}
I = 10^{10.6} x 10^{-12}
I of power mower = 0.0398 W/m^{2}
- intensity of the rock music
115 = 10 log \frac{I}{10^{-12}}
11.5 = log \frac{I}{10^{-12}}
10^{11.5} = \frac{I}{10^{-12}}
I = 10^{11.5} x 10^{-12}
I of rock music = 0.316 W/m^{2}
now the ratio of the intensity of the rock music to the power mower
= \frac{0.316}{0.0398}
= 8
A projectile is any object that is thrown, dropped or otherwise laughed into the air.
1) If it is dropped - it's motion is caused by just gravitation force
2) if it is thrown - it's motion is caused by gravitation force + force you applied to though it upwards
Answer:
Mechanical longitudinal waves are also called compressional or compression waves, because they produce compression and rarefaction when traveling through a medium, and pressure waves, because they produce increases and decreases in pressure.
Explanation:
Answer:
6.20×10⁴ V/m
Explanation:
The magnitude of electric field is:
E = √(Eₓ² + Eᵧ²)
where Eₓ = ∂φ/∂x and Eᵧ = ∂φ/∂y.
φ = 1.11 (x² + y²)^-½ − 429x
Eₓ = -0.555 (x² + y²)^-(³/₂) (2x) − 429
Eᵧ = -0.555 (x² + y²)^-(³/₂) (2y)
Evaluating at (0.003, 0.003):
Eₓ = -44034 V/m
Eᵧ = -43605 V/m
The magnitude is:
E = 61971 V/m
Rounded to three significant figures, the strength of the electric field is 6.20×10⁴ V/m.
the answer would be false
hope I helped and goodluck
:)