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3 years ago

The ground -state electron configuration contains 6p unpaired electrons .

Chemistry

1 answer:

yulyashka [42]3 years ago

4 0

Oh okay thanks for the information (Btw what is actually your question

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Calculate the energy of a photon with a frequency of 9.78 x 1021 Hz.

Alex_Xolod [135]

Answer:

9.98538 kilohertz

Explanation:

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3 years ago

GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g

JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of $H_2$ gas and 1 mole of $Br_2$ liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

$H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ$

Divide the equation by 2.

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

4 0

3 years ago

14. The following are a list of the four parts of John Dalton's atomic theory Indicate which of

Damm [24]

Answer:

all matter is made of tiny particles called atom

5 0

2 years ago

What is formula mass of glucose C2H12O6

Delvig [45]

Glucose has empirical formula C6H12O6. So its formula mass can be calculated from that: 12.01x6 + 1.008x12 + 16.00x6 = 72.06 + 12.096 + 96.00 = 180.156 which needs to be rounded to two decimals to get 180.16 g/mole<span>.</span>

3 0

3 years ago

A chemist is looking for an element that reacts similarly to the element lithium (LI). Which would be the best choice?

MatroZZZ [7]

Letter d, because they are both alkali metals (group one)

8 0

3 years ago

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